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Reptile [31]
3 years ago
9

Given the sequence 7, 12, 17, 22

Mathematics
2 answers:
Schach [20]3 years ago
8 0
4n+3 hope this helps good luck
Mila [183]3 years ago
5 0
I think it is either the top answer or the the bottom answer! goodluck!
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What is 8.89 × 1010 in standard notation?
SSSSS [86.1K]

Answer:

8978.9

Step-by-step explanation:

MULTIPLY THE THE GIVEN AND

8.89  ×  1010 = 8978.9

THEN THE RESULT WOUD BE THE STANDARD NOTATION.

8 0
3 years ago
The diameter of the base of the cone measures 8 units. The height measure 6 units. What is the volume of the cone?
ivolga24 [154]

Answer:

The  volume of the cone is  100.48 units³ approximately

Step-by-step explanation:

To find the volume of a cone with a diameter of 8 unit   and height of 6 units, we will follow the steps below;

first, write down the formula for calculating the volume of a cone

v= πr²\frac{h}{3}

where v is the volume of the cone

r is the radius    and h is the height of the cone

from the question given, diameter d = 8 units  but d=2r    which implies  r=d/2

r=8/2 = 4 units

Hence r= 4 units

height = 6 units

π is a constant and is ≈ 3.14

we can now proceed to insert the values into the formula

v= πr²\frac{h}{3}

v ≈ 3.14 × 4² × 6/3

v  ≈ 3.14 × 16 × 2

v ≈ 100 .48 units³

Therefore the  volume of the cone is  100 .48 units³ approximately

6 0
3 years ago
PLZ HELP ME MARK AS BRAINLY HOWEVER ANSWERS FIRST!!!!
Darina [25.2K]

Answer:

115

Step-by-step explanation:

When multiplying a fraction by a fraction, you multiply the numerator by the numerator and same with the denominator. 13 times 4 =52,  7 times 9=63, 52+63=115.  Hope this helps!

8 0
3 years ago
What is the answer?
lukranit [14]
A) 4/9 = g/36
b) g = 16
c) 52 total pints, 8pints in a gallon, so 6.5 gallons
8 0
3 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(
Umnica [9.8K]

Answer:

(a) A_1 and A_2 are indeed mutually-exclusive.

(b) \displaystyle P(A_1\; \cap \; B) = \frac{1}{20}, whereas \displaystyle P(A_2\; \cap \; B) = \frac{1}{25}.

(c) \displaystyle P(B) = \frac{9}{100}.

(d) \displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}, whereas P(A_1 \; |\; B) = \displaystyle \frac{4}{9}

Step-by-step explanation:

<h3>(a)</h3>

P(A_1 \; \cap \; A_2) = 0 means that it is impossible for events A_1 and A_2 to happen at the same time. Therefore, event A_1 and A_2 are mutually-exclusive.

<h3>(b)</h3>

By the definition of conditional probability:

\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}.

Rearrange to obtain:

\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot  P(A_1) = 0.25 \times 0.20 = \frac{1}{20}.

Similarly:

\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot  P(A_2) = 0.80 \times 0.05 = \frac{1}{25}.

<h3>(c)</h3>

Note that:

\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}.

In other words, A_1 and A_2 are collectively-exhaustive. Since A_1 and A_2 are collectively-exhaustive and mutually-exclusive at the same time:

\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}.

<h3>(d)</h3>

By Bayes' Theorem:

\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}.

Similarly:

\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}.

6 0
3 years ago
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