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Reptile [31]
3 years ago
9

Given the sequence 7, 12, 17, 22

Mathematics
2 answers:
Schach [20]3 years ago
8 0
4n+3 hope this helps good luck
Mila [183]3 years ago
5 0
I think it is either the top answer or the the bottom answer! goodluck!
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11,520 yds, you multiply the numbers
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3 years ago
$15,000 is invested for 15 years with an APR of 4.2% and monthly compounding.
Phoenix [80]

Answer:

51-54: Simple Interest. Calculate the amount of money you will have in the following accounts after 5 years, assuming that you eam simple interest 51. You deposit $ 700 in an account with an annual interest rate of 4% 52. You deposit $1200 in an account with an annual interest rate of 3% 53. You deposit $3200 in an account with an annual interest rate of 3.5% 54. You deposit $1800 in an account with an annual interest rate of 3.8% 55-56: Simple versus Compound Interest. Complete the following tables, which show the performance of two investments over a 5-year period. Round all figures to the nearest dollar. 55 Suzanne deposits $3000 in an account that earns simple interest at an annual rate of 2.5%. Derek deposits $3000 in an account that earns compound interest at an annual rate of 2.5%. Suzanne's Suzanne's Derek's Annual | Derek's Year Annual Interest Balance Interest Balance rest formula to the stated pe 57-62: Compound Interest. Use the compound interest form compute the balance in the following accounts after the state riod of time, assuming interest is compounded annually. 57. $10,000 is invested at an APR of 4% for 10 years. 58. $10,000 is invested at an APR of 2.5% for 20 years. 59. $15,000 is invested at an APR of 3.2% for 25 years. 60. $3000 is invested at an APR of 1.8% for 12 years. 61. 55000 is invested at an APR of 3.1% for 12 years. 62. $ 40,000 is invested at an APR of 2.8% for 30 years. 63-70: Compounding More Than Once a Year. Use the appropriate compound interest formula to compute the balance in the following accounts after the stated period of time. 63. $10,000 is invested for 10 years with an APR of 2% and quarterly compounding. 64. $2000 is invested for 5 years with an APR of 3% and daily compounding 65. $25,000 is invested for 5 years with an APR of 3% and daily compounding 66. $10,000 is invested for 5 years with an APR of 2.75% and monthly compounding. 67. $2000 is invested for 15 years with an APR of 5% and monthly compounding 68. $30,000 is invested for 15 years with an APR of 4.5% ana daily compounding. 69. $25,000 is invested for 30 years with an APR of 3.7% quarterly compounding. 70. $15,000 is invested for 15 years with an APR of 4.2% monthly compounding. 71-74. Annual.

Hope this helps

7 0
2 years ago
An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio
olga2289 [7]

Answer:

a) E(Y) = \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:

E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60

b) E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1

And then the expected value would be:

E(100Y^2) = 100*1.1= 110

Step-by-step explanation:

We assume the following distribution given:

Y       0       1        2        3

P(Y) 0.60 0.25  0.10  0.05

Part a

We can find the expected value with this formula:

E(Y) = \sum_{i=1}^n Y_i P(Y_i)

And replacing we got:

E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60

Part b

If we want to find the expected value of 100 Y^2 we need to find the expected value of Y^2 and we have:

E(Y^2) = \sum_{i=1}^n Y^2_i P(Y_i)

And replacing we got:

E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1

And then the expected value would be:

E(100Y^2) = 100*1.1= 110

4 0
3 years ago
Can you make more arrays with 8 tiles then 9
Charra [1.4K]
No because u have to have 9 or 9 or 8 and 8
5 0
3 years ago
Read 2 more answers
In the figure, the measure of angle 9 is 80 degrees and the measure of angle 5 is 68. Find the measure of each angle.
murzikaleks [220]

Answer/Step-by-step explanation:

Given:

m<9 = 80°,

m<5 = 68°

Lines w and v are parallel to each other.

m<1 = m<9 (corresponding angles theorem)

m<1 = 80°

m<2 + m<1 = 180° (linear pair)

m<2 + 80° = 180° (substitution)

m<2 = 180° - 80°

m<2 = 100°

m<3 = m<1 (vertical angles are congruent)

m<3 = 80°

m<4 = m<2 (vertical angles are congruent)

m<4 = 100°

m<6 + m<5 = 180° (linear pair)

m<6 + 68° = 180° (substitution)

m<6 = 180° - 68°

m<6 = 112°

m<7 = m<5 (vertical angles)

m<7 = 68°

m<8 = m<6 (vertical angles)

m<8 = 112°

m<10 = m<2 (corresponding angles)

m<10 = 100°

m<11 = m<9 (vertical angles)

m<7 = 80°

m<12 = m<10 (vertical angles)

m<12 = 100°

m<13 = m<5 (corresponding angles)

m<13 = 68°

m<14 = m<6 (corresponding angles)

m<14 = 112°

m<15 = m<13 (vertical angles)

m<15 = 68°

m<16 = m<14 (vertical angles)

m<16 = 112°

6 0
3 years ago
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