You can figure this out by setting up an equation and make
x= tens digit
y= ones digit
y + 8 =x (tens digit 8 more than ones)
also we know that
y>0
x>0
since the 10s digit and 1s digit cannot be more than one number, we can say
0 < y > 10
0 < x > 10
since x has to be greater than 0 but less than 10, there is only one number that would fit into the equation for y
2 + 8 = 10
(y cannot equal 2 because than x is equal to 10 and it must be less than)
1 + 8 = 9
( y can be 1 since x is less than 10)
so it would be
y= 1
x= 9
the number would be 91
hope this helped!
Your answer is 2’3’3!! (2*3*3 = 18)
hopefully this helps, good luck bud! :)
Answer:
The desired equation is y = (-8/3)x + 26/3.
Step-by-step explanation:
Moving from (1,6) to (4, -2) involves an increase of 3 in x and a decrease of 8 in y. Thus, the slope of the line thru these two points is m = rise / run = -8/3.
Using the slope-intercept form of the eq'n of a straight line and inserting the data given (slope = m = -8/3, x = 4, y = -2), we get:
y = mx + b => -2 = (-8/3)(4) + b, or -2 = -32/3 + b
Multiply all terms by 3 to clear out the fraction:
-6 = -32 + 3b.
Then 26 = 3b, and b = 26/3.
The desired equation is y = (-8/3)x + 26/3.
Remember that to find the vertical asymptotes of rational functions, we just need to set the denominator equal to zero and solve for the variable, in this case
, so lets do it:
As you can see, our rational functions has
2 vertical asymptotes: 
and
Distribute the 12 by multiplying so it would be 96b-60 and they aren’t like terms so that’s as far as you can go
