All categories

2 years ago

Reduce to simplest form. -5/8 + (-8/5) Need this ASAP (khan academy)

Mathematics

2 answers:

alina1380 [7]2 years ago

7 0

Here is an attachment with the answer. I hope this helps.

coldgirl [10]2 years ago

6 0

Answer:

the answer is 2.225.........

You might be interested in

Mike traveled to Greensboro by car. Going there took 6 hours, and the return trip was four hours. Mike averaged a speed of 81 mi

Marat540 [252]

Answer: 64.8 mph

Step-by-step explanation:

Given

Arriving time is 6 hours

return time is 4 hours

The average speed of returning 81 mph

Distance traveled while returning

$\Rightarrow d=81\times 4=324\ miles$

the average speed of the entire trip is

$\Rightarrow v_{avg}=\dfrac{2\times 324}{6+4}=\dfrac{648}{10}=64.8\ mph$

4 0

2 years ago

Which number line shows the solution to the inequality -3x - 5 < -2 ?

Inessa05 [86]

The answer to his is A

3 0

2 years ago

PLEASE PLEASE HELP ASAP WILL MARK BRAINLIEST

Lelu [443]

Answer:

The answer is 216.

Step-by-step explanation:

4 0

2 years ago

Find the dot product of u and v. u=(7,15) v = (-5,2)

nignag [31]

Answer:

A.... -5

Step-by-step explanation:

-35 + 30 = -5

5 0

2 years ago

The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to

Firdavs [7]

Rewrite the boundary lines y = -1 - x and y = x - 1 as functions of y :

y = -1 - x ==> x = -1 - y

y = x - 1 ==> x = 1 + y

So if we let x range between these two lines, we need to let y vary between the point where these lines intersect, and the line y = 1.

This means the area is given by the integral,

$\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy$

The integral with respect to x is trivial:

$\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy$

For the remaining integral, integrate term-by-term to get

$\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}$

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line y = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

6 0

2 years ago