<span>–4(x + 3) ≤ –2 – 2x

>>.....-4x -12 </span>≤ -2 -2x

>> -12 +2 ≤ +2x

>> - 10 ≤ 2x

>> -5 ≤ x............>> x >= -5

This answer is not represented in the pictures you attached

The line starts in x = -5 and goes up to infinity

3 0

2 years ago

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Which function is graphed below?

hoa [83]

Option B. y = 3 (one-third) Superscript x is the function that is graphed in this question.

<h3>How to solve the problem</h3>

We have exponential functions to be of the form abˣ

This can be written in the form of f(x) = $3\frac{1}{3} ^x$

So it crosses through the point (0, 3).

From the way that the curve passes through the circle, we can see that the it is said to pass through at (0, 3) and approaches y = 0 in quadrant 1

Hence this would put our answer to be y = 3 (one-third) Superscript x

Read more on coordinate planes here

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2 years ago

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Use the t-distribution and the sample results to complete the test of the hypotheses. Use a significance level. Assume the resul

Ksenya-84 [330]

Answer:

Test statistic = 1.3471

P-value = 0.1993

Accept the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 4

Sample mean, $\bar{x}$ = 4.8

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 2.3

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 4\\H_A: \mu \neq 4$

We use two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{4.8 - 4}{\frac{2.3}{\sqrt{15}} } = 1.3471$

Now, we calculate the p-value.

P-value = 0.1993

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept it.

3 0

3 years ago