1.5/75 = 0.02
0.02 x 100 = $2
Therefore the original price was $2.
4x + 2y = 8
When x = -2: 4x + 2y = 8
4(-2) + 2y = 8
-8 + 2y = 8
+ 8 + 8
2y = 16
2 2
y = 8
(x, y) = (-2, 8)
When x = 1: 4x + 2y = 8
4(1) + 2y = 8
4 + 2y = 8
- 4 - 4
2y = 4
2 2
y = 2
(x, y) = (1, 2)
When x = 3: 4x + 2y = 8
4(3) + 2y = 8
12 + 2y = 8
- 12 - 12
2y = -4
2 2
y = -2
(x, y) = (3, -2)
Answer:
The number of ways can the 3 prizes be awarded = 4 ways
Step-by-step explanation:
It is given that,
There are 4 cyclists in a race. There will be a first place, a second place, and a third place prize awarded.
<u>To find the possible number of ways</u>
There are 4 cyclists
The number of prizes = 3
The number of ways can the 3 prizes be awarded = 4C₃
<u>To find 4C₃</u>
4C₃ = (4 * 3 * 2)/(1 * 2 * 3) = 4 ways
Therefore the number of ways can the 3 prizes be awarded = 4 ways
Yes, it's all right. There's no fault