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alexandr402 [8]
3 years ago
6

While mining, Jason found a large metal bar that weighed 24 ounces. Jason was also able to determine that the bar had 6 ounces o

f copper. What percent of the weight of the bar was copper? Round your answer to the nearest whole number if necessary.
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0
25% 6 divided by 24 will give you the percentage of copper in the bar
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Schach [20]
I don't know sorry :(
8 0
2 years ago
What is f(x)=14−0.5x? <br><br> solve for f(30)
UkoKoshka [18]
The function f(x) is a function of the variable x.

To solve the function for x = 30, just plug in 30 for x.

14 - 0.5(30) = -1

f(30) = -1
3 0
3 years ago
Given that(4,6) is on the graph of f(x) find the corresponding point for the function f(-4x)
Len [333]

Answer:

(-1,6)

Step-by-step explanation:

Given that(4,6) is on the graph of f(x)

f(-4x) means x is multiplied by -4

When x is multiplied by -1  then there will be reflection over y axis

We multiply every point by -1. so multiply the x values of the given point (4,6) by -1

New point is (-4,6)

If any number is multiplied with x then there will be a horizontal compression or stretch.

4 is multiplied with x , so there will be horizontal compression because 4 is greater than 1

To get new point, we divide the x values by 4 for compression

we already got (-4,6) after multiplying by -1

Now we divide the x coordinate -4 by 4 = -1

So corresponding point for the function f(-4x) is (-1,6)


5 0
3 years ago
15 is 30% of what number?
dangina [55]
#1---> let the number you are trying to find be x for the following questions

30%*x=15
x=15/30%
x=50

#2
10%*x=14
x=14/10%
x=140

#3
(4/32)*100
 is the same as (1/8)*100= 12.5%

#4
1%* x=11
x=11/1%
x=1100

by the way * means multiply

5 0
3 years ago
Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

which at the point (-1, 4, 3) has a value of

\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

4 0
3 years ago
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