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alexandr402 [8]
3 years ago
6

While mining, Jason found a large metal bar that weighed 24 ounces. Jason was also able to determine that the bar had 6 ounces o

f copper. What percent of the weight of the bar was copper? Round your answer to the nearest whole number if necessary.
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0
25% 6 divided by 24 will give you the percentage of copper in the bar
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Daniel spent 3 hours babysitting for his brother. He and the children played games for 1 3/4 hours and watched television for 1/
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Answer:

He spent 3/4 of an hour reading stories

Step-by-step explanation:

Sorry I dont have time :(

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2 years ago
The temperature in frostville was at 50*F at midnight,and it dropped at a constant rate for the next 10 hours.
bazaltina [42]

After 10 hours the temperature is shown on the graph as 30 degrees.

50 degrees - 30 degrees = 20 degrees.

The temperature dropped 20 degrees in 10 hours.

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20 degrees / 10 hours = 2 degrees per hour.

Because the temperature dropped, the change would be negative.

The answer is D. -2 degrees per hour.

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3 years ago
Find the measurement of the angle indicated for each trapezoid
suter [353]

Answer:

45

Step-by-step explanation:

5 0
3 years ago
I need to understand question 14 and 15 and the last one cut off for tens in one
sp2606 [1]

                                                 Question # 14

Given the numbers

10     11     12     13     14     15     16     17     18     19     20

Let 'x' be the number

The condition breakdown:

I am less than 20.

  • So the number 'x' must be less than 20 i.e. x < 20

I am more than 13.

  • So the number 'x' must be greater than 13 i.e. x > 13

I am less than 17.

  • So the number 'x' must be less than 17 i.e. x < 17

Finally:

I am 4 more than 12

i.e. 12+4 = 16

Thus, the number is x = 16

                                               Question # 15

Part a)

Given the numbers

10     11     12     13     14     15     16     17     18     19     20

Let 'x' be the number

The condition breakdown:

I am more than 10.

  • x > 10

I am less than 20.

  • x < 20

I am more than 12.

  • x > 12

I am less than 15.

  • x < 15

As the numbers left after all the conditions are fulfilled are 13 and 14.

  • But the last condition is, of the numbers that left, the number is greater than all the remaining numbers.

So, from the remaining number 13 and 14;

14 > 13

Thus, the number x = 14

Part b)

Drawing the number 14 in the place value:

          Chart

Tens                Ones

1                         4

6 0
3 years ago
Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo
NikAS [45]

Answer:

[tex]4608\sqrt{3}[/tex]

Step-by-step explanation:

1. \sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}

2. \sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}   <em>factoring 96</em>

<em>since \sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}</em>

3. \sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>using exponent rule - (a^{b}) ^{c} = a^{bc}</em>

<em> \sqrt{2^{5} } = 2^{5/2}</em>

4. 2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}

<em>doing some simple simplification and 4=2^{2}  and 6=2*3</em>

5. 2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}

<em>collecting the roots on one side and applying exponent rule</em>

6. \sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}

<em>Applying exponents rule on all \sqrt{3} and \sqrt{2}</em>

<em>7. 2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}</em>

<em>combining all powers of 2</em>

8. 2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}

<em>Simplifying</em>

9. 2^{9} *3^{2}\sqrt{3}

10. 512*9\sqrt{3}

11. 4608\sqrt{3}

3 0
3 years ago
Read 2 more answers
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