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alexandr402 [8]

3 years ago

6

While mining, Jason found a large metal bar that weighed 24 ounces. Jason was also able to determine that the bar had 6 ounces o

f copper. What percent of the weight of the bar was copper? Round your answer to the nearest whole number if necessary.

1 answer:

tino4ka555 [31]3 years ago

5 0

25% 6 divided by 24 will give you the percentage of copper in the bar

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sammy [17]

First multiply each term by 24(the common denominator found by 8×3) to remove the fractions and make things easier.
$24(5) + 24( \frac{x - 2}{3} ) = 24( \frac{x + 3}{8} )$
This will give you,
$120 + 8(x - 2) = 3(x + 3)$
Then just continue to simplify and isolate the variable.
$120 + 8x - 16 = 3x + 9$
$8x + 104 = 3x + 9$
$5x = - 95$
$x = - 19$

7 0

2 years ago

Amanda purchased a 30 year $10,000 bond at par value with a 4% coupon. What is the total value of the coupons

klasskru [66]

Amanda purchased a 30 year $10,000 bond at par value with a 4% coupon.

We find the coupon amount each year

Coupon amount = actual amount of bond * 4%

= 10,000 * 0.04 = 400

Coupon amount for every year = 400

Total value of coupons for 30 years = 400 * 30 = 12000

$12,000 is the total value of the coupons

8 0

2 years ago

Read 2 more answers

The function f is continuous on the closed interval [1,15] and has the values shown on the table above. Let g(x) = ∫f(t) dt [1,x

Anna11 [10]

We're looking for the two values being subtracted here. One of these values is easy to find:

<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.

The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:

</span><span>Each integral breaks down like so:

(3-1)*f(1)=4

(6-3)*f(3)=9

(10-6)*f(6)=16

(15-10)*f(10)=10.

So, the sum of all these integrals is 39, which means g(15)=39.

Then, g(15)-g(1)=39-0=39.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!

3 0

3 years ago

Read 2 more answers

6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the

MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

$a_1$ the horizontal distance between the first observer and the ballonist

$a_2$ the horizontal distance between the second observer and the ballonist

$\alpha _1$ and $\alpha _2$ the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

$S=a*h$ (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

$S=S_1+S_2$ (equation 2)

$S_1=a_1*h$

But we can write $S_1$ in terms of $\alpha _1$ , like this:

$\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}$

And for $S_2$ will be the same:

$S_2=\frac{h^{2} }{\tan(\alpha _2)}$

Replacing in the equation 2:

$S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})$

And replacing in the equation 1:

$h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}$

So, we can replace all the known data in the last equation:

$h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft$

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0

2 years ago

Suppose that the functions g and h are defined for all real numbers r as follows. gx) -4x +5 h (x) = 6x write the expressions fo

aleksandr82 [10.1K]

Answer: Our required values would be -10x+5, 2x+5 and -25.

Step-by-step explanation:

Since we have given that

g(x) = -4x+5

and

h(x) = 6x

We need to find (g-h)(x) and (g+h)(x).

So, (g-h)(x) is given by

$g(x)-h(x)\\\\=-4x+5-6x\\\\=-10x+5$

and (g+h)(x) is given by

$g(x)+h(x)\\\\=-4x+5+6x\\\\=2x+5$

and (g-h)(3) is given by

$-10(3)+5\\\\=-30+5\\\\=-25$

Hence, our required values would be -10x+5, 2x+5 and -25.

5 0

3 years ago