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alexandr402 [8]
3 years ago
6

While mining, Jason found a large metal bar that weighed 24 ounces. Jason was also able to determine that the bar had 6 ounces o

f copper. What percent of the weight of the bar was copper? Round your answer to the nearest whole number if necessary.
Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0
25% 6 divided by 24 will give you the percentage of copper in the bar
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A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
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Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

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Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

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∴ V= 4x³-50x²+15x

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V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

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x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

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∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

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