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Yakvenalex [24]
3 years ago
13

5. There are two kinds of products (called DA and GA) produced in your company every day. Alsothere are two kinds of materials (

denoted by A and B) in need One DA costs one unit of A, one unit of B: one GA costs one unit of A, two units of B. You get $3000 when you sell one DA and $5000 for one GA. The supply of the two materials every day is 12,22. a)What is the maximal profit $ b) How many DA and GA should be produced every day to obtain this maximal profit? Number of DA = Number of GA
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
8 0

Answer:

  • a) $56000
  • b) DA = 2, GA = 10

Step-by-step explanation:

<u>Given</u>

  • DA = A + B ⇒ $3000
  • GA = A + 2B ⇒ $5000
  • Number of A = 12
  • Number of B = 22

<u>We can see from the equations that</u>

  • GA - DA = B ⇒ $2000 and
  • A = $1000 and B = $2000 in terms of profit

<u>So greater use of unit B brings greater profit. We don't want any unit is left over, so get this equation.</u>

  • A + B = 12
  • A + 2B = 22

Is the equation set to indicate use of the units A and B

<u>Solving we get </u>

  • A = 2 and
  • B = 10

<u>It this case all the units are used and profit is maximum</u>

  • 2*$3000 + 10*$5000 = $56000
  • Number of DA = 2
  • Number of GA = 10
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Step-by-step explanation:

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2 years ago
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The whole numbers a and b are divisible by c. Is a+b divisible by c? Is b−a divisible by c? Explain your reasoning.
gizmo_the_mogwai [7]

Answer:

a+b is divisible by c since d and e are also whole numbers.

b-a is divisible by c since d and e are also whole numbers.

Step-by-step explanation:

Let a, b whole number that are divisible by c. Then, we have that d = \frac{a}{c} and e = \frac{b}{c}, which are also whole numbers. We proceed to prove that a + b is divisible by c:

1) d = \frac{a}{c}, e = \frac{b}{c}, a, b , c, d, e \in \mathbb{Z} Given

2) d + e = \frac{a}{c}+\frac{b}{c} Compatibility with addition

3) d+e = a\cdot c^{-1}+b\cdot c^{-1} Definition of division

4) d + e = c^{-1}\cdot (a+b) Commutative and distributive properties

5) d+e = (a+b) \cdot c^{-1} Commutative properties

6) d+e = \frac{a+b}{c} Definition of division/Result

Therefore, a+b is divisible by c since d and e are also whole numbers.

We proceed to prove that b-a is divisible by c:

1) d = \frac{a}{c}, e = \frac{b}{c}, a, b , c, d, e \in \mathbb{Z} Given

2) d\cdot (-1) = \frac{a}{c}\cdot (-1) Compatibility with multiplication

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7) e+d\cdot (-1) = [b+a\cdot (-1)]\cdot c^{-1} Commutative properties.

8) e + d\cdot (-1) = \frac{b+a\cdot (-1)}{c} Definition of division

9) e-d = \frac{b-a}{c} (-1)\cdot a = -a/Definition of subtraction

Therefore, b-a is divisible by c since d and e are also whole numbers.

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3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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