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Alinara [238K]
3 years ago
6

Can you help me? Look at the last question I posted as an example.

Mathematics
2 answers:
ivolga24 [154]3 years ago
8 0

Step-by-step explanation:

1. (-3/2, 1)

2. (6,-3)

3. (8/3, 2)

4. <u>(</u><u>2</u><u>,</u><u>-4</u><u>)</u>

<u>5</u><u>.</u><u>(</u><u>-3</u><u>,</u><u>-1</u><u>)</u>

<u>6</u><u>.</u><u> </u><u>(</u><u>0</u><u>,</u><u>3</u><u>/</u><u>2</u><u>)</u>

<u>7</u><u>.</u><u> </u><u>(</u><u>4</u><u>,</u><u> </u><u>-2</u><u>)</u>

<u>8</u><u>.</u><u>(</u><u>8</u><u>,</u><u>2</u><u>)</u>

<u>9</u><u>.</u><u> </u><u>(</u><u>0</u><u>,</u><u>0</u><u>)</u>

Bas_tet [7]3 years ago
3 0
Here I found the answer key for it
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If 4 is the constant of proportionality is this equation correct? y = 4x + 2​
max2010maxim [7]

Answer:

4 is not the constant. 2 is.

Step-by-step explanation:

In the following equation: y = 4x + 2

x and y are variables. x can be any given number, and y would be the resulting answer.

4 is not the constant, because the product it will produce varies on what x will be.

2 is a constant, because it will not change regardless what is put into x. It will continue to stay as 2.

6 0
2 years ago
Which is equivalent to 3 cube root 125
aleksklad [387]
Do you mean 3 \sqrt[3]{125} or \sqrt[3]{125}
remember that \sqrt[n]{x^m}=x^\frac{m}{n}
resolve the \sqrt[3]{125} part first\sqrt[3]{125}=\sqrt[3]{5^3}=5^\frac{3}{3}=5^1=5

so
3 \sqrt[3]{125}=3*5=15 or \sqrt[3]{125} =5not sure which one you mean
7 0
3 years ago
Read 2 more answers
Which graph represents -
11Alexandr11 [23.1K]

Answer:

3rd

Step-by-step explanation:

5 0
2 years ago
HELP I NEED HELP ASAP
pentagon [3]

Answer:

Answer

Step-by-step explanation:

The answer is d because if you at 17 to 197 you'll get 203

6 0
2 years ago
Suppose flights on standard routes between two given cities use on average 3,087 gallons of kerosene with standard deviation of
Radda [10]

Answer:

15.866%

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 3,282 gallons of kerosene

μ is the population mean = 3,087 gallons of kerosene

σ is the population standard deviation = 195 gallons

For x > 3282 gallons

z = 3282 - 3087/195

z = 1

Probability value from Z-Table:

P(x<3282) = 0.84134

P(x>3282) = 1 - P(x<3282) = 0.15866

Converting to percentage

0.15866 × 100 = 15.866%

The percent of flights on these particular routes that will burn more than 3,282 gallons of kerosene is 15.866%

3 0
2 years ago
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