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trapecia [35]
2 years ago
14

For every 4 students, 3 like peanut butter and jelly sandwiches. If there are 12 students, how many like peanut butter and jelly

sandwiches?​
Mathematics
2 answers:
amid [387]2 years ago
5 0

Answer:

9 students

Step-by-step explanation:

3/4 students like pbj sandwiches

4 * 3 = 12

3 * 3= 9

9/12

9 students like pbj sandwiches

Kazeer [188]2 years ago
4 0

Answer:

9 students

Step-by-step explanation:

12 divide 4 = 3

3 x 3 = 9

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Express with radical signs instead of fractional exponents. Rationalize the denominator.
CaHeK987 [17]

x^{\frac{1}{2}} = \sqrt[2]{x} and 3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}} so

3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x}  = \frac{\sqrt{x}}{\sqrt{3}}

and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

Your answer is \frac{\sqrt{3x}}{3}

5 0
3 years ago
A particle moves on a circle through points which been marked 0,1,2,3,4 (in a clockwise order). At each step it has a probabilit
Sedaia [141]

Answer:

Step-by-step explanation:

Given data:

SS={0,1,2,3,4}

Let probability of moving to the right be = P

Then probability of moving to the left is =1-P

The transition probability matrix is:

\left[\begin{array}{ccccc}1&P&0&0&0\\1-P&1&P&0&0\\0&1-P&1&P&0\\0&0&1-P&1&P\\0&0&0&1-P&1\end{array}\right]

Calculating the limiting probabilities:

π0=π0+Pπ1                 eq(1)

π1=(1-P)π0+π1+Pπ2     eq(2)

π2=(1-P)π1+π2+Pπ3    eq(3)

π3=(1-P)π2+π3+Pπ4    eq(4)

π4=(1-P)π3+π4             eq(5)

π0+π1+π2+π3+π4=1

π0-π0-Pπ1=0

→π1 = 0

substituting value of π1  in eq(2)

(1-P)π0+Pπ2=0

from

π2=(1-P)π1+π2+Pπ3  

we get

(1-P)π1+Pπ3 = 0

from

π3=(1-P)π2+π3+Pπ4

we get

(1-P)π2+Pπ4 =0

from π4=(1-P)π3+π4  

→π3=0

substituting values of π1 and π3 in eq(3)

→π2=0

Now

π0+π1+π2+π3+π4=0

π0+π4=1

π0=0.5

π4=0.5

So limiting probabilities are {0.5,0,0,0,0.5}

4 0
3 years ago
Tickets to a school play cost $3 for students and $8 for adults. on opening night, $1,000 was collected and 150 tickets sold. us
Salsk061 [2.6K]
S+a=150
3s+8a=1000
a=-s+150
3s-8s+1200=1000
-5s=-200
s=40
a=110
40 student and 110 adult tickets were sold
6 0
3 years ago
List the values in ascending order -94%,-8/9, -.925, -9/10
luda_lava [24]
-94%, -.925, -9/10, -8/9
7 0
2 years ago
M ÷ n - 3 (m + n) with m=-10 and n=-2
avanturin [10]
Given:
m/n-3(m+n)
m=-10 and n=-2

Solving:

-10/-2-3(-10-2) Since m=-10 and n=-2, we substitute them in for the values since they have an equal relationship.

Now, follow Orders of Operations: PEMDAS


-10/-2-3(-12) Simplify parentheses (P)
There are no Exponents (E)
Multiplication (M) and Division (D) are =, so we do whatever operation comes from the left to right.
-10/-2=5 Division comes first on the left.
therefore:
5-3(-12)

-3(12)=-36, Multiplication is last on the right.
therefore:
5-36

5-36=-31 After M/D, we do Addition and Subtraction, which are also =, so we do them left to right.

Therefore -10/-2-3(-10-2)=-31
3 0
2 years ago
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