Answer:
Angle 5 = 122
Step-by-step explanation:
Assume EB and AD intersect each other at point C
As this is the circle, four points A,B,D,E are all on the circle, so that we have:
+) m∠EBD = 1/2 measure of arc ED (small arc)
=> m∠EBD = 1/2 . 66 = 33 degree
=> m∠CBD = 33
+) m∠ADB = 1/2 measure of arc AB (small arc)
=>m∠ADB = 1/2 . 50 = 25 degree
=>m∠CDB = 25 degree
In the triangle CDB, we have total measure of three internal angles is 180 degree
=> Angle 5 + m∠CDB + m∠CBD = 180
=> Angle 5 + 25 + 33 = 180
=> Angle 5 = 180 -25 - 33 = 122 degree
<span>There is an equation to solve this. It looks like:
Sum of interior angles = (n - 2) * 180 degrees
where n is the number of sides of the n-gon, which is 37.</span>
First you would do -30x5 which equals -150 then 2-150 equals -148
