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pshichka [43]
3 years ago
7

This writing prompts is hard

Mathematics
1 answer:
Solnce55 [7]3 years ago
7 0
A.) Simplifying the equation would lead you to 15x^2-3x+9

b.) You know your answer is correct because you're adding the two polynomials together. 9x^2+6x^2 is 1tx^2. Now you have 2x-5x and since the negative is bigger, you get -3x. Then 5+4 is 9. You have no like terms therefore your answer is 15x^2-3x+9
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Please help I’m confused.
Ede4ka [16]

Answer:

What is the most common month?  That is the answer

Step-by-step explanation:

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3 years ago
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3⋅35=n Express your answer as a simple fraction or improper fraction in simplest form.
Flauer [41]

Answer:

n=105 just multiply 3*35 youll get 105


8 0
3 years ago
Helllohello help please if you want -
zaharov [31]

Answer:

True

Step-by-step explanation:

Let's take a problem such as 3x-2=6

To isolate the variable, you must get rid of everything on one side and essentially do the inverse to the other side. We see -2, so you have to add 2 to each side.

Now you have 3x=8

Next, we device each side by 3. Right now, x is being multiplied by 3 so we have to do the inverse.

Answer is x = 8/3 or 2.666666666666667

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3 years ago
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What is the slope of a line parallel to the line with equation 2x−5y=9?
katrin2010 [14]

Answer:

For this one the parallel slope is going to be 2/5

Step-by-step explanation:

4 0
2 years ago
We intend to estimate the average break time of Dunder Mifflin employees. From a previous study, we believe that the average tim
arsen [322]

Answer:

The minimum sample size that we should consider is of 60 employees.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

We want our 99 percent confidence interval to have a margin of error of no more than plus or minus 2 minutes. What is the smallest sample size that we should consider?

We need to find n for which M = 2, \sigma = 6

So

M = z*\frac{\sigma}{\sqrt{n}}

2 = 2.575*\frac{6}{\sqrt{n}}

2\sqrt{n} = 2.575*6

Simplifying by 2

\sqrt{n} = 2.575*3

(\sqrt{n})^{2} = (2.575*3)^{2}

n = 59.67

Rounding up

The minimum sample size that we should consider is of 60 employees.

6 0
3 years ago
Read 2 more answers
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