I NEED HELP ASAP! I just need help on these 2 I don't understand!

Mathematics

2 answers:

Kaylis [27]4 years ago

5 0

Answer:

Question 1 - Option C

Question 2 - Option B

Step-by-step explanation:

Question 1:

Volume of box = Length x Breadth x Height

Length = 40 ft, Breadth = 10 ft and Height = 10 ft.

Volume of bus = 40 x 10 x 10 = 4 x 10³ ft³

Option C is the correct answer.

Question 2:

Volume of sphere $=\frac{4}{3} \pi r^3$

Radius = Half of diameter = 20 mm

Volume of ball $=\frac{4}{3} \pi* 20^3=3.35*10^4mm^3=3*10^4mm^3$

Option B is the correct answer.

jarptica [38.1K]4 years ago

3 0

1 is C <span>4 × 10^3 ft^3
</span>and
2 is B <span>3× 10^4 mm^3</span>

You might be interested in

In triangle xyz, z2 = x2 + y2. triangle xyz has sides x, qy, z opposite to the corresponding vertices x, y, z which equation is

Mrac [35]

${\text{In triangle XYZ}},{\text{ square of one side is equal to the sum of squares of other two sides, }} \hfill \\ {\text{,i}}{\text{.e}}{\text{., if triangle XYZ has sides of measure }}x\,{\text{unit, }}y\,{\text{unit and }}z\,{\text{unit}} \hfill \\ {\text{opposite to the corresponding vertices }}X,{\text{ }}Y\,{\text{and }}Z\,{\text{respectively, then}} \hfill \\ {z^2} = {x^2} + {y^2} \hfill \\ {\text{Since, the given triangle satisfying the condition of Pythagoras theorem, }} \hfill \\{\text{thus, the given triangle would be a right angled triangle and thereby the measure}} \hfill \\{\text{of one angle of triangle will be a right angle say at vertex Z}}{\text{.}} \hfill \\\Rightarrow m\left( {\angle Z} \right) = 90^\circ \hfill \\\Rightarrow m\left( {\angle XZY} \right) = 90^\circ \hfill \\{\text{Thus,the measure of angle XZY is equal to }}90{\text{ }}degrees. \hfill \\$