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Mila [183]
3 years ago
15

Which is the graph of the system of inequalities y>4/5x- 1/5 and y<2x+6

Mathematics
1 answer:
lawyer [7]3 years ago
5 0

Answer:

The Second Graph (RIGHT)

Step-by-step explanation:

You dont really need to solve it, but you can see that the second graph crosses the y-axis at +6, and the first one doesnt....

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You decide to get an estimate on the cost of repairs for the green food truck. The mechanic explains that the cost of the repair
I am Lyosha [343]

Answer:

you save labor : 3562.50

Step-by-step explanation:

You want to calculate for labor.

labor = 3/5 (parts)

labor + parts = $9500 (total costs)

3/5 parts + parts =9500

3/5 parts + 5/5 parts = 9500

8/5 parts=9500

5/8(8/5 parts) = 5/8 (9500)

‘parts = 5937.50

labor=3562.50 (3/5 x 5937.50)

total = 9500

7 0
3 years ago
According to records in a large hospital, the birth weights of newborns have a symmetric and bell-shaped relative frequency dist
Kamila [148]

Answer:

15.9% of babies are born with birth weight under 6.3 pounds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.8 pounds

Standard Deviation, σ = 0.5

We are given that the distribution of  birth weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(birth weight under 6.3 pounds)

P(x < 6.3)

P( x < 6.3) = P( z < \displaystyle\frac{6.3 - 6.8}{0.5}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < -1) = 0.159 = 15.9\%

15.9% of babies are born with birth weight under 6.3 pounds.

8 0
3 years ago
Is a theater there are 28 rows in each row there are 32 seats, each ticket coasts £19.75
DedPeter [7]

Answer:

£17696

Step-by-step explanation:

28*32= 896

896*19.75= 17696

7 0
3 years ago
Read 2 more answers
Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y
irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

y'(x)= x^2y(x)-\frac12y^2(x)

Putting the value of y'(x) in equation (1)

y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))

Substituting x =0 and h= 0.2

y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]

\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]    [∵ y(0) =3 ]

\Rightarrow y(0.2)\approx 2.7

Substituting x =0.2 and h= 0.2

y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]

\Rightarrow y(0.4)\approx  2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]

\Rightarrow y(0.4)\approx 1.9926

Substituting x =0.4 and h= 0.2

y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]

\Rightarrow y(0.6)\approx  1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]

\Rightarrow y(0.6)\approx 1.6593

Substituting x =0.6 and h= 0.2

y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]

\Rightarrow y(0.8)\approx  1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]

\Rightarrow y(0.6)\approx 0.8800

Substituting x =0.8 and h= 0.2

y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]

\Rightarrow y(1.0)\approx  0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]

\Rightarrow y(1.0)\approx 0.9152

Therefore the value of y(1)= 0.9152.

4 0
3 years ago
Given m||n, find the value of x.<br><br> (2x+9)<br> (7X+24)
motikmotik

<em>Given, 9−7x=5−3x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x</em>

<em>Given, 9−7x=5−3xPut x terms on one side and constants on another side.⇒9−5=7x−3x⇒4=4x⇒x= </em><em>4</em><em>/</em><em>4</em><em> </em><em> =1</em>

<em> =1Hence, required solution is x=1.</em>

<em> </em><em>p</em><em>lease </em><em>mark </em><em>me</em><em> a</em><em> </em><em>brainlist</em><em> answer</em><em> </em><em>I </em><em>need </em><em>only </em><em>1</em><em> </em><em>ok</em>

8 0
3 years ago
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