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77julia77 [94]
3 years ago
7

Which number supports the given conjecture?

Mathematics
2 answers:
TiliK225 [7]3 years ago
6 0
D. 36 because 36/ 2= 18 36/ 3= 12 36/ 6= 6
choli [55]3 years ago
3 0
A. 16 is divisible by 2 but not divisible by 3
B. 23 is not divisible neither by 2 nor 3
C. 27 is not divisible by 2, however it's divisible by 3
D. 36 is divisible both by 2 and 3

So the only number we can focus on is 36:

36 ÷ 2 = 18
36 ÷ 3 = 12
36 ÷ 6 = 6

Answer: D, 36 supports the given conjecture.
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Help geometry hw will give brainliest
Ber [7]

Answer:

34 degrees

Step-by-step explanation:

Angle K is similar to Angle R, and Angle R is 34 degrees. So Angle K is also 34 degrees.

Hope it helps!

4 0
3 years ago
Given the diagram below what is the length of segment EF
frosja888 [35]

Answer:

C is the closest.,

Step-by-step explanation:

I am assuming that the 2 trapezoids CBEF and EFDA are similar (they are similar if the 3 horizontal lines are parallel).

Corresponding sides are in the same ratio , so:

3.4 / EF = EF / 7.6

EF^2 = 3.4 * 7.6 =  25.84

EF = 5.08

6 0
3 years ago
Read 2 more answers
Solve each equation. Leave the answer as an improper fraction. 16x^2 = 49​
zmey [24]

Answer:

7/4

Step-by-step explanation:

5 0
2 years ago
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Help solve 4 and 5 please
Sloan [31]

Answer:

Step-by-step explanation:

4). a). If the diagonals of a parallelogram are congruent, then it must be a RECTANGLE.

b). If the diagonals of a parallelogram are perpendicular, then it must be a SQUARE.

c). If the diagonals of a parallelogram bisect the angles of the parallelogram, then it must be a RHOMBUS.

d). If the diagonals of a parallelogram are perpendicular and congruent, then it must be a SQUARE.

e). If a parallelogram has four congruent sides, then it must be a SQUARE.

5). Given quadrilateral SELF is a rhombus.

a). All sides of a rhombus are equal,

   Therefore, ES = EL = 25

b). Diagonals of a rhombus bisects the opposite angles,

   Therefore, m∠ELS = m∠FLS

    3x - 2 = 2x + 7

    3x - 2x = 7 + 2

    x = 9

c). Diagonals of the rhombus bisect the opposite angles, and adjacent angles are supplementary.

m∠ELF = 2(m∠ELS) = 2(2y - 9)

m∠LES = 2(m∠LEF) = 2(3y + 9)

And 2(2y - 9) + 2(3y + 9) = 180

(2y - 9) + (3y + 9) = 90

5y = 90

y = 18  

6 0
3 years ago
I think it’s the third one
Zigmanuir [339]
It’s third to the one
7 0
2 years ago
Read 2 more answers
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