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Triss [41]
3 years ago
12

Janis is preparing a financial document. She needs to use the dollar symbol placed above the number key 4. Which key will Janis

use along with the number key, to get the dollar symbol?
a. tab
b. ctrl
c.shift
d. alt
Computers and Technology
2 answers:
andreyandreev [35.5K]3 years ago
3 0

C. Shift hold down to shift and then press 4

Anuta_ua [19.1K]3 years ago
3 0

Janis will hold down the shift button then she she will click the number 4 and then it will give you $

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Type the correct answer in the box. Spell the word correctly. Which framework can be used to develop cross-platform applications
kaheart [24]

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Xamarin

Explanation:

Xamarin framework can be used to develop cross-platform applications.

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A laptop computer is smaller than desktop computer. True or false
alina1380 [7]

Answer:

true

Explanation:

4 0
3 years ago
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An anagram of a string is another string with the same characters in the same frequency, in any order. For example 'ab', 'bca, a
nlexa [21]

Answer:

from collections import Counter

def anagram(dictionary, query):

   newList =[]

   for element in dictionary:          

       for item in query:

           word = 0

           count = 0

           for i in [x for x in item]:

               if i in element:

                   count += 1

                   if count == len(item):

                       newList.append(item)

   ans = list()

   for point in Counter(newList).items():

       ans.append(point)

   print(ans)        

mylist = ['jack', 'run', 'contain', 'reserve','hack','mack', 'cantoneese', 'nurse']

setter = ['ack', 'nur', 'can', 'con', 'reeve', 'serve']

anagram(mylist, setter)

Explanation:

The Counter class is used to create a dictionary that counts the number of anagrams in the created list 'newList' and then the counter is looped through to append the items (tuple of key and value pairs) to the 'ans' list which is printed as output.

4 0
3 years ago
You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. Yo
Andrei [34K]

Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

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}

else

m = x[x.length/2];

8 0
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