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horsena [70]
3 years ago
7

What will the computer do in response to a line of code reading # name = input("What is your name?")

Computers and Technology
1 answer:
lorasvet [3.4K]3 years ago
4 0

Answer:

it would show What is your name? on the screen and you would be able to input your name

Explanation:

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Can someone please give me the 3.6 code practice answer I will mark you brainlyist
Stolb23 [73]

3.6 Code Practice Question:

Write a program to input 6 numbers. After each number is input, print the biggest of the number entered so far:

Answer:

nums = []

biggest = 0

for i in range(6):

    num = int(input("Number: "))

    nums.append(num)

    if(i == 0):

         print("Largest: "+str(nums[0]))

         biggest = nums[0]

    else:

         if nums[i]>biggest:

              print("Largest: "+str(nums[i]))

              biggest = nums[i]

         else:

              print("Largest: "+str(biggest))

                       

Explanation:

This question is answered using python

This line declares an empty list

nums = []

This line initalizes the biggest input to 0

biggest = 0

This iteration is perfoemed for 6 inputs

for i in range(6):

This prompts user for input

    num = int(input("Number: "))

This appends user input to the list created

    nums.append(num)

For the first input, the program prints the first input as the largest. This is implemented in the following if condition

<em>     if(i == 0):</em>

<em>          print("Largest: "+str(nums[0]))</em>

<em>          biggest = nums[0]</em>

For subsequent inputs

    else:

This checks for the largest input and prints the largest input so far

<em>          if nums[i]>biggest:</em>

<em>               print("Largest: "+str(nums[i]))</em>

<em>               biggest = nums[i]</em>

<em>          else:</em>

<em>               print("Largest: "+str(biggest))</em>

<em />

3 0
3 years ago
A 10 Superscript negative 910−9​-F capacitor ​(11 nanofaradnanofarad​) is charged to 5050 V and then disconnected. One can model
vredina [299]

Answer:

Explanation:

i) On a cold day, Capacity = (66 X 910 X 10∧-9) F

Charge, Q = (66 X 910 X 10∧-9) X 5050 = 0.30 Columb

Current, I= 5050/131013 = 0.039 Amp (where Resistance = 131013 ohms)

Time, t= 0.30/0.039 = 7.7 seconds

ii) On a humid day, Capacity = (77 X 910 X 10∧-9) F

Charge, Q = ( 77 X 910 X 10∧-9) X 5050 = 0.35 Columb

Current, I= 5050/6106 = 0.83 Amp ( where Resistance = 6106 ohms)

Time, t= 0.35/0.83 = 0.42 h or  0.42 X 60 mins = 25 mins

7 0
3 years ago
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