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Neporo4naja [7]
3 years ago
9

(4/9)-¹ ?????????? what is it? -9/4 -4/9 9/4

Mathematics
1 answer:
Elis [28]3 years ago
8 0
Im not sure on the syntax here, but i assume the question is (4/9)^-1

(4/9)^-1
= (4^-1)/(9^-1)

A negative power is an inverse of the positive power
i.e. x^-2 = 1/x^2
This is because if we have say x^3/x^5 we simplify it by cancelling x^3 which gives 1/x^2.
Another way to think of it is to subtract the power of the bottom x from the power of the top x: 3-5 = -2 so x^3/x^5 = x^-2.
I hope this explains how negitive powers are the inverse of the positive power.

So....
(4^-1)/(9^-1)
= 9/4
Because the inverse of 4 is 1/4 and the inverse of 1/9 is 9
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For each value of determine whether it is a solution to 2x - 7 = -23
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Answer:

x = -8

Step-by-step explanation:

-23 + 7 = -16

-16 ÷ 2 = -8

2 × -8 =-16 - 7 = -23

8 0
2 years ago
Jori has 7 boxes of books,with each box holding the same number of books.he has126 books in all how many books are there per box
bazaltina [42]
Let b be the number of books in a box.  Then we can say that the total number of books is equal to the number of boxes times the number of books per box.

7b=126  divide both sides by 7

b=18

So there are 18 books per box.
7 0
2 years ago
Is 0.088 greater than, less than or equal to 0.88
pogonyaev
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8 0
3 years ago
The mean of 19 numbers is 35.
sladkih [1.3K]
First we find the sum of all values using the mean formula.

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Then we compute the mean.

If you have any additional questions ask.

4 0
2 years ago
Read 2 more answers
Is binomial Theorem JUST Pascal's triangle? Or is there another equation...?
iragen [17]
Pascal's triangle is a visual representation of the coefficients involved in a binomial expansion. The nth row of the triangle gives the coefficients of the terms in the expansion of (a+b)^{n-1}.

The triangle itself looks like

\begin{matrix}1\\1&1\\1&2&1\\1&3&3&1\end{matrix}

and so on, while the expansions for n=1,2,3,4 are

(a+b)^{1-1}=(a+b)^0=1
(a+b)^{2-1}=(a+b)^1=1a+1b
(a+b)^{3-1}=(a+b)^2=1a^2+2ab+1b^2
(a+b)^{4-1}=(a+b)^3=1a^3+3a^2b+3ab^2+1b^3

and so on.

The binomial theorem says that

(a+b)^{n-1}=\displaystyle\sum_{k=0}^{n-1}\binom{n-1}ka^{n-1-k}b^k
(a+b)^{n-1}=\dbinom{n-1}0a^{n-1}b^0+\dbinom{n-1}1a^{n-2}b^1+\cdots+\dbinom{n-1}{n-2}a^1b^{n-2}+\dbinom{n-1}{n-1}a^0b^{n-1}
(a+b)^{n-1}=\dbinom{n-1}0a^{n-1}+\dbinom{n-1}1a^{n-2}b+\cdots+\dbinom{n-1}{n-2}ab^{n-2}+\dbinom{n-1}{n-1}b^{n-1}

The numbers in the nth row of the triangle are just \dbinom{n-1}k, with k=0,1,\ldots,n-2,n-1.

So no, the binomial theorem and Pascal's triangle are not the same thing. Pascal's triangle is a way of organizing the pattern exhibited by the result of the binomial theorem. 
4 0
3 years ago
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