Question

Solve 6x^2 - 42 = 0 for the exact values of x

Answer 1

Answer:

The values of x are

$x=-\sqrt{7} , x=\sqrt{7}$

Step-by-step explanation:

we have

$6x^{2}-42=0$

Solve for x

Adds 42 both sides

$6x^{2}-42+42=0+42$

$6x^{2}=42$

Divide by 6 both sides

$6x^{2}/6=42/6$

simplify

$x^2=7$

square root both sides

$x=\pm\sqrt{7}$

therefore

The values of x are

$x=-\sqrt{7} , x=\sqrt{7}$