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Rudiy27
3 years ago
5

Solve 6x^2 - 42 = 0 for the exact values of x

Mathematics
1 answer:
GREYUIT [131]3 years ago
6 0

Answer:

The values of x are

x=-\sqrt{7} , x=\sqrt{7}

Step-by-step explanation:

we have

6x^{2}-42=0

Solve for x

Adds 42 both sides

6x^{2}-42+42=0+42

6x^{2}=42

Divide by 6 both sides

6x^{2}/6=42/6

simplify

x^2=7

square root both sides

x=\pm\sqrt{7}

therefore

The values of x are

x=-\sqrt{7} , x=\sqrt{7}

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