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1 year ago

What is the radius of 22cm of a circle

Mathematics

2 answers:

algol131 year ago

4 0

Answer:

11 cm

Step-by-step explanation:

To find radius just divide diameter of 22 by 2. The answer will be 11.

zhuklara [117]1 year ago

4 0

11cm the radius is the width half way across the circle so you take 22cm and divide it by 2 and that’s how you get 11cm

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7 in.

fgiga [73]

258 cubic inches

Since the boxes are kind of on their own—>
First box: 7*2*12 = 168
Second box: 5*2*9=90
168+90 = 258

6 0

3 years ago

Unknown to a medical researcher, 6 out of 25 patients have a heart problem that will result in death if they receive the test dr

Fiesta28 [93]

Using the hypergeometric distribution, it is found that there is a 0.0002 = 0.02% probability that exactly 6 patients will die.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

The values of the parameters for this problem are:

N = 25, k = 6, n = 8.

The probability that exactly 6 patients will die is P(X = 6), hence:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 6) = h(6,25,8,6) = \frac{C_{6,6}C_{19,2}}{C_{25,8}} = 0.0002$

0.0002 = 0.02% probability that exactly 6 patients will die.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

#SPJ1

8 0

1 year ago

Please someone what is the total surface area of this pryamid

Dimas [21]

Answer:

$\large\boxed{C.\ (25+25\sqrt3)\ in^2}$

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

$A_S=a^2$

a - length of side

The formula of an area of an equilateral triangle:

$A_T=\dfrac{a^2\sqrt3}{4}$

a - length of side

Clculate the areas:

SQURE:

$A_S=x^2\ in^2$

TRIANGLE:

$A_T=\dfrac{x^2\sqrt3}{4}\ in^2$

The SURFACE AREA of a square pyramid:

$S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3$

Put x = 5:

$S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2$

7 0

3 years ago

Part C

makkiz [27]

a = 1, b =14 and y-coordinate is 6 when x = 0.

Solution:

Let us first write the equation of a line.

Take the points are (2, 2) and (6, 10).

Slope of the line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{10-2}{6-2}$

$$m=\frac{8}{4}$

m = 2

Point-slope formula:

$y-y_1=m(x-x_1)$

y - 10 = 2(x - 2)

y - 10 = 2x - 4

Add 10 on both sides,we get

y = 2x + 6

Equation of a line is y = 2x + 6.

To find (a, 8), substitute x = a and y = 8 in the equation,

8 = 2a + 6

Subtract 6 from both sides, we get

2 = 2a

a = 1

To find (4, b), substitute x = 4 and y = b in the equation,

b = 2(4) + 6

b = 8 + 6

b = 14

Substitute x = o in the equation.

y = 2(0) + 6

y = 6

The y-coordinate is 6 when x = 0.

7 0

2 years ago

2+23+8x9-3+7+2x8x9x2x4+3

Ber [7]

Answer:

1256

Step-by-step explanation:

Just multiply and add each number

3 0

2 years ago

What is the radius of 22cm of a circle​

What is the radius of 22cm of a circle