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irina1246 [14]
2 years ago
10

What is the radius of 22cm of a circle​

Mathematics
2 answers:
algol132 years ago
4 0

Answer:

11 cm

Step-by-step explanation:

To find radius just divide diameter of 22 by 2. The answer will be 11.

zhuklara [117]2 years ago
4 0
11cm the radius is the width half way across the circle so you take 22cm and divide it by 2 and that’s how you get 11cm
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Simplify square root of 24 times square root of 2x times square root of 3x
sveticcg [70]
\sqrt{24} * \sqrt{2x} * \sqrt{3x} =  \sqrt{2*2*2*3}* \sqrt{2*x} * \sqrt{3*x} =  \sqrt{2*2*2*2*3*3*x*x} = 2*2*3*x = 12x
3 0
4 years ago
In ΔABC, the measure of ∠C=90°, the measure of ∠A=47°, and BC = 3.5 feet. Find the length of AB to the nearest tenth of a foot.
luda_lava [24]
It’s 164.5 that would be ur answer
7 0
3 years ago
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Can you help with a please on 46
valentina_108 [34]
3/5
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5 0
3 years ago
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What is the equation of a line that passes through point R(3,7) and has a slope of 6?
djyliett [7]
The answer in slope intercept form is y = 6x-11

If you want the answer in standard form, then it would be 6x-y =11

notes:
* Slope intercept form is y = mx+b
* Standard form is Ax+By = C
=====================================

Explanation:

The given slope is m = 6
The line goes through (x,y) = (3,7)

Plug those three values into the equation below. Isolate b
y = mx+b
7 = 6*3+b
7 = 18+b
7-18 = 18+b-18 ... subtract 18 from both sides
-11 = b
b = -11

So because m = 6 and b = -11, this means y = mx+b turns into y = 6x-11

The answer in slope intercept form is y = 6x-11

To convert to standard form Ax+By = C, we just have to get all the x and y terms together on the same side. I'm going to move the y term to the right side and move the 11 to the left side

y = 6x-11
y+11 = 6x-11+11
y+11 = 6x
y+11-y = 6x-y
11 = 6x-y
6x-y = 11

The answer in standard form is 
6x-y = 11
which is a different way to write the same line

4 0
3 years ago
The general form of an parabola is 2x2−12x−3y+12=0 .
Murljashka [212]

Answer:

The standard form of the parabola is (x-3)^2=4*\frac{3}{8}(y+2)

Step-by-step explanation:

The standard form of a parabola is

(x-h)^2=4p(y-k).

In order to convert 2x^2-12x-3y+12=0 into the standard form, we first separate the variables:

2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y

we now divided both sides by 2 to remove the coefficient from 2x^2 and get:

x^2-6x+6=\frac{3}{2}y.

We complete the square on the left side by adding 3 to both sides:

x^2-6x+6+3=\frac{3}{2}y+3

x^2-6x+9=\frac{3}{2}y+3

(x-3)^2=\frac{3}{2}y+3

now we bring the right side into the form 4p(y-k) by first multiplying the equation by \frac{2}{3}:

\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2

and then we multiplying both sides by \frac{3}{2} to get

(x-3)^2=\frac{3}{2} (y+2).

Here we see that

4p=\frac{3}{2}

\therefore p=\frac{3}{8}

Thus, finally we have the equation of the parabola in the standard form:

\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}

5 0
3 years ago
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