An example of an item where you would need to find the area of a square is a square table.
An example of an item where you would need to find the area of a rectangle is a phone that has a rectangular shape.
<h3>How to calculate the area?</h3>
It's important to note that the area of a square is the multiplication of its sides by itself. For example, if the side is 4cm, the area will be:
= 4²
= 4 × 4.
= 16cm²
The area of a rectangle will be:
= Length × Width
Assuming length and width are 5cm and 2cm. This will be:
= 5 × 2
= 10cm²
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I suppose you mean

Then

and the difference quotient is

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with
Answer:
see below
Step-by-step explanation:
1. yes
2. no, 4.82 x 10^4
3, no, 9.9 x 10^-4
4. no, 3.6 x 10^6
5. yes
6. no, 7.8 x 10^-4
B.....is has division...................