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3 years ago

Algebra 1 -5c+d=2c find for c

Mathematics

2 answers:

beks73 [17]3 years ago

8 0

Answer:

d/7 = c

Step-by-step explanation:

-5c+d=2c

Add 5c to each side

-5c+5c+d=2c+5c

d = 7c

Divide each side by 7

d/7 = 7c/7

d/7 = c

nekit [7.7K]3 years ago

6 0

Answer:

d/7 = c

Step-by-step explanation:

STEP

Simplify —

Equation at the end of step

c d

(((—•c)-d)-(2•—))+d

2 c

STEP

Simplify —

Equation at the end of step

c 2d

(((— • c) - d) - ——) + d

2 c.

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3x+2(x-5)=25 show your work

Zanzabum

Answer:

x = 7

Step-by-step explanation:

Expand 3x+2(x-5)=25 which looks like

3x+2x-10=25

Add similar elements: ( 3x+2x = 5x)

5x-10=25

Add 10 to both sides

5x-10+10 = 25 + 10

Simplfy

5x = 35

Divide both sides by 5

5x ÷ 5 = 35 ÷ 5

Simplfy:

x = 7

have a wonderful day

8 0

3 years ago

A. Write an equation for the sentence. Six times a number n is 132

lakkis [162]

Answer:

6n=32

Step-by-step explanation:

3 0

3 years ago

What is the measure if each interior angle of a 15-gon

olya-2409 [2.1K]

Answer:

The sum of the interior angles of the 15-gon $=\:2340^0$

Each interior angle of the regular polygon $=\:156^0$

Step-by-step explanation:

As we know that

In any convex polygon, if we may start at one vertex and draw the diagonals to all the other vertices, we would form triangles,

The number of triangles thus formed would always 2 LESS than the number of sides.

The sum of measure of the angles of any triangle is 180°.

Thus,

The sum of the interior angles of the 15-gon will be:

$13\:\times\:180\:=\:2340^0$

Also

15-gon is regular, it means this total $2340^0$ is shared in equal proportion among the 15 interior angles.

And

Each interior angle of the regular polygon will be: $\frac{2340^{0} }{15}=156^{0}$

Therefore, we conclude that:

The sum of the interior angles of the 15-gon $=\:2340^0$

Each interior angle of the regular polygon $=\:156^0$

Keywords: regular polygon, 15-gon, triangle

Learn more about polygon from brainly.com/question/11932357

#learnwithBrainly

3 0

3 years ago

A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a

Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

$p^4 (1-p) + (1-p)^4 p$

(b)

The expected numbers of flips needed would be

$\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1} = 1/p$

Therefore, suppose that $p = 0.5$ , then the expected number of flips needed would be 1/0.5 = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

$p^4 (1-p)$

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

$(1-p)^4p$