A giraffe can run up to 46.93 ft. per second. How far could a giraffe run in 1.8 seconds? Justify your answer

Write the fraction as a decimal 64 100

erastovalidia [21]

Answer:

0.64 is a decimal and 64/100 or 64% is the percentage for 64/100.

Step-by-step explanation:

6 0

2 years ago

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Given c=(2.4,0.45) and d = (7,-4) find the direction of 5c+4d

kakasveta [241]

Answer:

The direction of 5c + 4d is approximately 19.0° clockwise with

the positive part of x-axis

Step-by-step explanation:

* Lets talk about the direction of a vector

- If the vector is (x , y), then

# Its magnitude is √(x² + y²)

# Its direction is tan^-1 (y/x)

- The direction is the angle between the positive part of x-axis and

the vector

* Lets solve the problem

∵ c = (2.4 , 0.45) and d = (7 , -4)

- To find 5c + 4d , multiply the two coordinates of c by 5 and the two

coordinates of d by 4

# Multiply c by 5

∴ 5c = [5(2.4) , 5(0.45)]

∴ 5c = (12 , 2.25)

# Multiply d by 4

∴ 4d = [4(7) , 4(-4)]

∴ 4d = (28 , -16)

- Lets add 5c and 4d

∴ 5c + 4d = (12 , 2.25) + (28 , -16)

∴ 5c + 4d = [(12 + 28) , (2.25 + -16)]

∴ 5c + 4d = (40 , -13.75)

- The vector is in the 4th quadrant because the x-coordinate is

positive and the y-coordinate is negative

* Find the direction of 5c + 4d

∵ The direction is tan^-1 (y/x)

∴ The direction is tan^-1 (-13.75/40) = -18.97°

* The direction of 5c + 4d is approximately 19.0° clockwise with

the positive part of x-axis

3 0

3 years ago

Order the set of numbers from least to greatest.<br><br><br> {2.5, 4, 23, 1, 5, 3, 0.66}

joja [24]

0.66, 1, 2.5, 3, 4, 5, 23

7 0

2 years ago

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Classify each figure as many ways as possible. Write : quadrilateral , trapezoid , parallelogram , rhombus , rectangle , or squa

allochka39001 [22]

2. Quadrilateral, rectangle, parallelogram

3. Quadrilateral, trapazoid

4. Quadrilateral

5 0

3 years ago

Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a

Anit [1.1K]

Answer:

Analyzed and Sketched.

Step-by-step explanation:

We are given $y=\frac{\ln\left(5x)}{x^2}$

To sketch the graph we need to find 2 components.

1) First derivative of y with respect to x to determine the interval where function increases and decreases.

2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

$y'=\frac{1-2\ln\left(5x)}{x^3}=0$

$x = \sqrt e/5$ is absolute maximum

$y''=\frac{6\ln\left(5x)-5}{x^4}=0$

$x=e^{5/6}/5$ is the point concavity changes from down to up.

Here, x = 0 is vertical asymptote and y = 0 is horizontal asymptote.

The graph is given in the attachment.

4 0

2 years ago