Answer:
13. -4 14. -11 15. 
Step-by-step explanation:
13. (1-3-10)/3
14. (-15+4-22)/3
15. (-7.5+3-6.5)/3
Okay, so I'm assuming you want to know the intersection?
-5 = -1/2x - 2
-3 = -1/2x
1/2x = 3
x = 6
(6, -5)
The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
brainly.com/question/14290572
#SPJ2
Let's figure this out. Step by step:
P / 6 = 9
P = 6(9)
P = 54 is your answer.
I hope this helps :)
