The formula is (x1+x2)/2 will give you the x of the mid point.
(y1+y2)/2 will give you the y of the mid point.
So, (3+9)/2= 6
And (6+8)/2=7
The mid point is (6:7)
Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
256, -256
Step-by-step explanation:
Absolute value simply removes the negative and does nothing to positive numbers
I think those were absolute value bars. not sure.
Answer:
7/23
Step-by-step explanation:
Each answer is 1.5/23 less than the previous
17/46 - 1.5/23 = 17/46 - 3/46 = 14/46 = 7/23
