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3 years ago

For the right triangle shown, which expression represents the length of CA?

Mathematics

1 answer:

strojnjashka [21]3 years ago

6 0

Step-by-step explanation:

The attached figure shows a right angled triangle right angle at C. It is required to find the length of CA.

Here, CA = x = perpendicular

BC = base

AB = hypotenuse =7

Angle B is 40 degrees

We know that the ratio of perpendicular to the hypotenuse is equal to sine of angle.

$\sin\theta=\dfrac{P}{H}\\\\\sin(40)=\dfrac{x}{7}$

x is length of CA

$x=7\sin(40)$

So, the correct option is (A).

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2 years ago

Read 2 more answers

-10x—16=14<br> -16x -6 = 14

Alla [95]

Answer: No solution

Step-by-step explanation:

-10x-16=14

-16x-6=14

-10x-16=-16x-6

-10x+16x-16=-16x+16x-6

6x-16=-6

6x-16+16=-6+16

6x=10

x=10/6

x=5/3

-16(5/3)-6=

-80/3-6*3/3=

-80/3-18/3=

(-80-18)/3=-98/3 $\neq$ 14

Hence, there is no solution

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1 year ago

Which equation shows a valid step in solving /2x-6+2x+6=0?

AfilCa [17]

An equation which shows a valid step that can be used to solve the given mathematical equation is $(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3$

<h3>What is an equation?</h3>

An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.

In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.

Take the cube of both sides, we have:

$\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3$