Hello,
$\left \{ {{y= \dfrac{1}{x+2} } \atop {y=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {\dfrac{1}{x+2}=x^2+2}} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x+2= \dfrac{1}{x^2+2} }} \right. \\\\

 \left \{ {{y= \dfrac{1}{x+2} } \atop {x= \dfrac{1}{x^2+2} -2}} \right. \\\\


$
x=-1.81053571 and y=<span> 5,27803957 </span>

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3 0

3 years ago

Read 2 more answers

According to Section 7, all bills for raising revenue shall originate in the ___.

Airida [17]

House of Representatives. :)

7 0

3 years ago

I need help answering these two questions . This is missing sides and Angles of Right Triangles

iren [92.7K]

1) Tanθ= opposite/adjacent
θ=Tan-1(9/7)
θ=52.125 = 52 degrees

2) Cosθ= adjacent/hypothesis
θ=Cos-1(5/12)
θ=65.376 = 65 degrees