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Anton [14]
3 years ago
10

Helpppppppppppppppppppppppp

Mathematics
2 answers:
Mkey [24]3 years ago
7 0

xy =-21~~.....(i)\\\\x+ y=20~~....(ii)\\\\\text{From equation (i):}\\\\xy = -21 \implies y = -\dfrac{21}x~~.....(iii)\\\\\text{Substitute y in equation (ii):}\\\\x - \dfrac{21}x  = 20\\\\\implies x^2 -20x -21= 0\\\\\implies x^2 - 21x + x-21=0\\\\\implies x(x-21)  +(x-21) =0\\\\\implies (x+1)(x-21)=0\\\\\implies x = -1 ~~\text{or}~~ x =21\\\\\text{Substitute x in equation (iii):}\\\\y = 21 ~~ \text{or}~~ y = -1\\\\\text{Hence,}~  (x,y)=(21,-1) ~~ \text{or}~~ (x,y) = (-1,21)

nirvana33 [79]3 years ago
5 0
I’d say 21 and -1 :)
21 * -1 = -21
21 - 1 = 20
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2. Find the common difference and the recursive formula. a. 22, 19, 16, 13, …
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Answer:

The common difference d is d = -3

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Step-by-step explanation:

We need to find the common difference and the recursive formula.

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First we will find common difference

The formula of arithmetic sequence is: a_n=a_1+(n-1)d

where a_n is nth term, a_1 is 1st term and d is the difference

Looking at the sequence we get: a_1=22, a_2=19

Using these values we can find d, the common difference

a_n=a_1+(n-1)d\\put\:n=2, a_2=19, a_1=22\\19=22+(2-1)d\\19=22+d\\d=19-22\\d=-3

So, the common difference d is d = -3

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The recursive formula is of type: a_n=a_{n-1}+d

We have found common difference d = -3

So, the recursive formula will be:

a_n=a_{n-1}+d\\a_n=a_{n-1}+(-3)\\a_n=a_{n-1}-3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

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