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Crazy boy [7]
1 year ago
10

If sin just answer the please lol i don't feel like typing ASAP

Mathematics
1 answer:
yaroslaw [1]1 year ago
5 0

Considering that the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

<h3>What are the signs of the sine and of the cosine in each quadrant?</h3>

  • Quadrant 1: Both positive.
  • Quadrant 2: Sine positive, cosine negative.
  • Quadrant 3: Both negative.
  • Quadrant 4: Sine negative, cosine positive.

Hence, since the sine is negative and that the cosine is positive, the angle is on the fourth quadrant, hence option C is correct.

More can be learned about quadrants at brainly.com/question/28021191

#SPJ1

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If x - 5y = 6, what is the value of y when<br> X= -4?<br> A:-2<br> B-2/5<br> C:2/5<br> D:2
zysi [14]

Answer:

I think the answer is D. 2

4 0
2 years ago
Read 2 more answers
The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,
klasskru [66]

Given:

The scale factor is s=\dfrac{1}{3} and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

(x,y)\to (k(x-a)+a,k(y-b)+b)

According to the given information, the scale factor is \dfrac{1}{3} and the center of dilation is at (4,2).

(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)            ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)

C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)

C(-2,11)\to C'(-2+4,3+2)

C(-2,11)\to C'(2,5)

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)

From the given figure it is clear that the image of point A is (8,4).

A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)

On comparing both sides, we get

\dfrac{1}{3}(m-4)+4=8

\dfrac{1}{3}(m-4)=8-4

(m-4)=3(4)

m=12+4

m=16

And,

\dfrac{1}{3}(n-2)+2=4

\dfrac{1}{3}(n-2)=4-2

(n-2)=3(2)

n=6+2

n=8

Therefore, the coordinates of point A are (16,8).

5 0
2 years ago
Bao is mixing flour and water to make dough the graph shows how much water he uses for different amounts of flour .How many lite
Allushta [10]

To know how many liters of water Bao use per liter of flour we have to divide the liters or flour so:

\frac{1}{3}=0.33

So Bao uses 0.33 or 1/3 of water per liter or flour

and to know hoy manu liters of flour Bao use per liter of water we have to made the oposite division so:

\frac{3}{1}=3

She use 3 liters of flour per liter of water

8 0
1 year ago
Find the equation of the line with slope 3/7 and that passes through the point (14, 0). Write your answer in the form y = mx + b
Allushta [10]

Answer:

y = 3/7x - 6

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Slope <em>m</em> = 3/7

Point (14, 0)

<u>Step 2: Find y-intercept </u><em><u>b</u></em>

  1. Substitute:                    0 = 3/7(14) + b
  2. Multiply:                        0 = 6 + b
  3. Isolate <em>b</em>:                       -6 = b
  4. Rewrite:                         b = -6

<u>Step 3: Write linear equation</u>

y = 3/7x - 6

7 0
3 years ago
Can an expert help with this
SVEN [57.7K]

The formula of an area of a circle:

A_O=\pi r^2

We have

r = 1.8 m

π ≈ 3.14

Substitute:

A_O=\pi\cdot1.8^2=3.24\pi\ m^2\approx3.24\cdot3.14=10.1736\ m^2\approx10.17\ m^2

7 0
2 years ago
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