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frosja888 [35]
3 years ago
12

What is the gcf and lcm

Mathematics
2 answers:
Vitek1552 [10]3 years ago
4 0
Least common multiple and greatest common factor
My name is Ann [436]3 years ago
3 0
GCF is Greatest Common Factor and LCM is Least Common Multiple

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choli [55]
90°
∠AEF is a right angle
∠CEF is a straight angle
m∠CEF = m∠CEA + m∠BEF
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3 years ago
Need help with 8,9, and 10
AnnZ [28]

Answer:C B A

2222222222222222222222222222222222222222222222222222222

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2 years ago
1.) You decide to order strands of LED lights for a party. Amazon charges
Vikki [24]

Answer:

11

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56.50-7=49.50

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Complete the inequality.<br><br> 11 gal ___ 28 qt<br><br> &gt;<br> &lt;<br> =
Sveta_85 [38]
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3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
2 years ago
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