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mixer [17]
3 years ago
13

In △ABC, CM is the median to AB and side BC is 12 cm long. There is a point P∈CM and a line AP intersecting BC at point Q. Find

the lengths of segments CQ and BQ, if P divides CM into CP:PM=1:2.

Mathematics
1 answer:
defon3 years ago
6 0

Answer:

  • CQ = 2.4 cm
  • BQ = 9.6 cm

Step-by-step explanation:

This development is ugly, but it works.

Let area ΔABC = 6a. Then area ΔAMC = 3a, and area ΔAPC = a. Similarly, area ΔBMC = 3a, and area ΔBPC = a.

Let area ΔCPQ = x. Then ...

... area ΔACQ = area ΔAPC + area ΔCPQ

... area ΔACQ = a + x

Define k such that BQ : CQ = k : 1. Then ...

... area ΔBPQ + area ΔCPQ = area ΔBPC

... kx + x = a = (k +1)x

The division of BC into parts of ratio k : 1 means ...

... area ΔABQ = k × area ΔACQ

... area ΔABQ + area ΔACQ = area ΔABC

... k × area ΔACQ + area ΔACQ = area ΔABC

... (k +1)(x +a) = 6a . . . . . . . area ΔACQ = x+a

... (k +1)x +(k +1)a = 6a . . . . . distributive property

... a + (k +1)a = 6a

... k +2 = 6 . . . . . . . . . . . . . . . divide by a, simplify

... k = 4

Now, we know BQ : CQ = 4 : 1, so ...

... BQ = 4/5 × 12 cm = 9.6 cm

... CQ = 1/5 × 12 cm = 2.4 cm

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2 mi. yd. I'm confused​
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Answer && Step-by-step explanation:

Obtain yards by multiplying miles by 1760

== 3520 yards

6 0
3 years ago
A brick layer is able to set 2.5 breaks in one minute how many bricks can you set an eight hours
frozen [14]

Answer:

<h2> In 8 hours he will set 1200 bricks</h2>

Step-by-step explanation:

In this problem, we are expected to estimate the number of bricks he can set in 8 hours.

let us convert hours to minutes we have

60 min make 1 hour

x min make 8 hours

cross multiply

x= 60*8

x= 480 min

We are assuming the same rate with which he sets 2.5 brick is the same as the rate with which he will set bricks for the 8 hours windows

so if the bricklayer sets

2.5 bricks in 1min

y bricks in 480 min

Cross multiply we have

y=2.5*480

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hence in 8 hours, he will set 1200 bricks

5 0
3 years ago
What is the length (magnitude) of the vector (2,-1)?
KiRa [710]

Answer:

\[\sqrt{5}\]

Step-by-step explanation:

The given vector is represented by (2,-1).

This can be represented in general form as (x,y) where x=2 and y=-1.

Magnitude of the vector represented as (x,y) is given by [\sqrt{x^{2}+y^{2}}\]

Evaluating for the given values of x and y,

\[\sqrt{2^{2}+(-1)^{2}}\]\[=\sqrt{4+1}\]

\[=\sqrt{5}\]

Length of the vector is \[\sqrt{5}\]

5 0
2 years ago
A market analyst is hired to provide information on the type of customers who shop at a particular store. A random survey is tak
sveta [45]

Complete question:

A market analyst is hired to provide information on the type of customers who shop at a particular store. A random survey is taken of 100 shoppers at this store. Of these 100, 73 are women. The shoppers The data is summarized below. we grouped in three age categories, under 30, 30 up to 50 and 50 and over. Women under 30 are 30, Men under 30 are 8 Women 30 to 50 are 25 and Men are 14 Women 50 and over are 18 and Men are 5.

Let W be the event that a randomly selected shopper is a woman. Let A be the event that a randomly selected shopper is under 30. a.) Find the probability of W. W (women Shoppers) = Find the probability of A. b.) Find the probability of A and W. c.) P (A and W) (Shoppers) d.) Find the probability of A or W. P(A or W) (Shoppers) e.) Find the probability of A given W

Answer:

A) P(W) = 73/100; B) P(A) = 38/ 100 C) 30 / 100

D) 81/100 E) 30/73

Step-by-step explanation:

- - - - - - - - Women Men Total

Under 30 - - - 30 - - - 8 - - 38

30 to 50 - - - - 25 - - 14 - - 39

50 & over - - - 18 - - - 5 - - -23

Totals - - - - - - 73 - - -27 - - 100

Recall:

Probability : P= (required outcome / Total possible outcomes)

A) probability of women shoppers: P(W)

Number of women shoppers = 73; total shoppers = 100

P(W) = 73/100

B) Probability of under 30: P(A)

= number of shoppers under 30 = 38

Tital number of shoppers = 100

P(A) = 38/ 100

C) probability of A and W; This is the probability that the selected person is a woman and under 30.

(W n A) = 30

= 30 / 100

D) probability of A or W:

P(A) + P(W) - P(A n W) :

(38 / 100 + 73 / 100 - 30 / 100) = (38+73-30) /100

= 81/100

E) probability of A given W:

P(A n W) / P(W) = 30/73

5 0
3 years ago
The sum of two consecutive integers is 57. If x is the integer what are the two numbers
ra1l [238]
The two numbers are 28 and 29.

5 0
3 years ago
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