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Tju [1.3M]
3 years ago
10

Lydia is buying cupcake ls for he brother birthday party. She brought 36 cupcakes total.Of the cupcakes she bought,5/6 of them w

ere vanilla cupcakes, which cost $1.50. The rest of the cupcakes were chocolate, which cost $2.25 each. What was the total Lydia spent on cupcakes
Mathematics
1 answer:
quester [9]3 years ago
3 0

Answer:

58.50

Step-by-step explanation:

First find out how many were vanilla and chocolate

vanilla: 5/6 * 36 = 30

Chocolate = total - vanilla = 36-30 =6

Cost for vanilla = 1.50*30 =45

Cost for chocolate 2.25*6 =13.5

Add the cost together

45+13.50

58.50

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Power Series Differential equation
KatRina [158]
The next step is to solve the recurrence, but let's back up a bit. You should have found that the ODE in terms of the power series expansion for y

\displaystyle\sum_{n\ge2}\bigg((n-3)(n-2)a_n+(n+3)(n+2)a_{n+3}\bigg)x^{n+1}+2a_2+(6a_0-6a_3)x+(6a_1-12a_4)x^2=0

which indeed gives the recurrence you found,

a_{n+3}=-\dfrac{n-3}{n+3}a_n

but in order to get anywhere with this, you need at least three initial conditions. The constant term tells you that a_2=0, and substituting this into the recurrence, you find that a_2=a_5=a_8=\cdots=a_{3k-1}=0 for all k\ge1.

Next, the linear term tells you that 6a_0+6a_3=0, or a_3=a_0.

Now, if a_0 is the first term in the sequence, then by the recurrence you have

a_3=a_0
a_6=-\dfrac{3-3}{3+3}a_3=0
a_9=-\dfrac{6-3}{6+3}a_6=0

and so on, such that a_{3k}=0 for all k\ge2.

Finally, the quadratic term gives 6a_1-12a_4=0, or a_4=\dfrac12a_1. Then by the recurrence,

a_4=\dfrac12a_1
a_7=-\dfrac{4-3}{4+3}a_4=\dfrac{(-1)^1}2\dfrac17a_1
a_{10}=-\dfrac{7-3}{7+3}a_7=\dfrac{(-1)^2}2\dfrac4{10\times7}a_1
a_{13}=-\dfrac{10-3}{10+3}a_{10}=\dfrac{(-1)^3}2\dfrac{7\times4}{13\times10\times7}a_1

and so on, such that

a_{3k-2}=\dfrac{a_1}2\displaystyle\prod_{i=1}^{k-2}(-1)^{2i-1}\frac{3i-2}{3i+4}

for all k\ge2.

Now, the solution was proposed to be

y=\displaystyle\sum_{n\ge0}a_nx^n

so the general solution would be

y=a_0+a_1x+a_2x^2+a_3x^3+a_4x^4+a_5x^5+a_6x^6+\cdots
y=a_0(1+x^3)+a_1\left(x+\dfrac12x^4-\dfrac1{14}x^7+\cdots\right)
y=a_0(1+x^3)+a_1\displaystyle\left(x+\sum_{n=2}^\infty\left(\prod_{i=1}^{n-2}(-1)^{2i-1}\frac{3i-2}{3i+4}\right)x^{3n-2}\right)
4 0
3 years ago
A coordinate plane with a line passing through (0, negative 3), (2, 0), and (4, 3).
Allushta [10]

Answer:

y= (3/2)x-3

Step-by-step explanation:

We need two points to find the equation of a line. Let's take (2,0) and (4, 3).

In the equation y=mx+b, m represents the slope. To find the slope, we can calculate the change in y/change in x. For (2,0) and (4,3), the change in y is 3-0=3 and the change in x is 4-2=2. Therefore, our slope is 3/2.

Then, in the equation y=mx+b, we can plug 3/2 in for m to get y = (3/2)x+b. To find b, we can plug one point in, such as (2.0), to get 0=(3/2)(2) + b, 0=3+b, and b=-3, making our equation

y= (3/2)x-3

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I will mark you as a brainliest!
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I think it is non-statistical as it has only one possible answer
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3 years ago
I was at the store, and saw two sizes of avocados being sold. The smaller size sold for $0.92 each. For what prices would the la
Firdavs [7]

Answer:

Large avocados should cost $ 1.83 or less to be a good deal.

Step-by-step explanation:

Since there are two types of avocado in the store, some small at $ 0.92 and others larger, to determine at what price large avocados would be a good deal, an equivalence must be established in this regard:

Thus, if two small avocados are equal to one large, buying two small avocados at $ 0.92 the total price would be $ 1.84. Therefore, any large avocado that sells for less than $ 1.84 would be a good deal. Thus, large avocados should cost $ 1.83 or less to be a good deal.

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san4es73 [151]
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6 0
3 years ago
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