All categories

4 years ago

A circular plate has circumference 33.3 inches. What is the area of this plate? Use 3.14 for pi

1 answer:

5 0

Answer:
≈
52.56
square inches
Explanation:
∙
circumference (C ) of a circle is
C
=
2
π
r

×
x
where r is the radius
⇒
2
π
r
=
25.7
←
solve for r
divide both sides by
2
π
2
π
r
2
π
=
25.7
2
π
⇒
r
=
25.7
2
π
←
exact value
∙
area (A )
=
π
r
2
⇒
A
=
π
×
(
25.7
2
π
)
2
≈
52.56 )
=
π
r
2
⇒
A
=
π
×
(
25.7
2
π
)
2
≈
52.56
to 2 dec. hope I helped bruh...

You might be interested in

Need help with this<br>please

artcher [175]

Answer:

$x^{\frac{2}{3} }$

Step-by-step explanation:

Exponent Rules: $(b^m)^n = b^{mn}$

Exponent Rules: $\frac{x^m}{x^n} = x^{m-n}$

Step 1: Write expression

$\frac{\sqrt[4]{x^3} }{x^{\frac{1}{12} }}$

Step 2: Rewrite radical

$\frac{{(x^3)^{\frac{1}{4} }} }{x^{\frac{1}{12} }}$

Step 3: Multiply powers (numerator)

$\frac{{x^{\frac{3}{4} }} }{x^{\frac{1}{12} }}$

Step 4: Subtract powers

$x^{\frac{2}{3} }$

8 0

4 years ago

Hello please help i’ll give brainliest but you gotta answer correctly

Mrrafil [7]

Answer:

the second one

Step-by-step explanation:

8 0

3 years ago

Are 15:10 and 3:2 ratios equivalent?

Grace [21]

YES if you simplify 15:10 by 5 since they can both be divided by 5 the ratio becomes 3:2

3 0

3 years ago

Read 2 more answers

Maci and I are making a small kite. Two sides are 10". Two sides are 5". The shorter diagonal is 6". Round all your answers to t

Art [367]

Answer:

A. 4".

B. Approximately 9.54".

C. Approximately 13.54".

Step-by-step explanation:

Please find the attachment.

Let x be the distance from the peak of the kite to the intersection of the diagonals and y be the distance from the peak of the kite to the intersection of the diagonals.

We have been given that two sides of a kite are 10 inches and two sides are 5 inches. The shorter diagonal is 6 inches.

A. Since we know that the diagonals of a kite are perpendicular and one diagonal (the main diagonal) is the perpendicular bisector of the shorter diagonal.

We can see from our attachment that point O is the intersection of both diagonals. In triangle AOD the side length AD will be hypotenuse and side length DO will be one leg.

We can find the value of x using Pythagorean theorem as:

$(AO)^2=(AD)^2-(DO)^2$

$x^{2}=5^2-3^2$

$x^{2}=25-9$

$x^{2}=16$

Upon taking square root of both sides of our equation we will get,

$x=\sqrt{16}$

$x=\pm 4$

Since distance can not be negative, therefore, the distance from the peak of the kite to the intersection of the diagonals is 4 inches.

B. We can see from our attachment that point O is the intersection of both diagonals. In triangle DOC the side length DC will be hypotenuse and side length DO will be one leg.

We can find the value of y using Pythagorean theorem as:

$(OC)^2=(DC)^2-(DO)^2$

Upon substituting our given values we will get,

$y^2=10^2-3^2$

$y^2=100-9$

$y^2=91$

Upon taking square root of both sides of our equation we will get,

$y=\sqrt{91}$

$y\pm 9.539392$

$y\pm\approx 9.54$

Since distance can not be negative, therefore, the distance from intersection of the diagonals to the top of the tail is approximately 9.54 inches.

C. We can see from our diagram that the length of longer diagram will be the sum of x and y.

$\text{The length of the longer diagonal}=x+y$