Answer:
denominators are zero for x=1
there is no solution
Step-by-step explanation:
We suspect your equation is supposed to be ...
10/(5x -5) +1/5 = 2/(x -1) . . . . . parentheses are required on denominators
The denominators will be zero for x=1.
This version of the equation has no solution. It simplifies to ...
2/(x-1) + 1/5 = 2/(x -1)
1/5 = 0 . . . . . subtract 2/(x-1) from both sides
There is no value of x that will make this equation true.
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<em>Alternative interpretation</em>
The way your equation is written, it must be interpreted according to the order of operations to be ...
(10/5)x -5 +1/5 = (2/x) -1 . . . . x=0 makes the denominator zero
2x -3.8 = 2/x
2x^2 -3.8x = 2 . . . . multiply by x
2(x^2 -1.9x +.95^2) = 2 +2(0.95^2)
(x -0.95)^2 = 1.9025
x = 0.95 ± √1.9025 ≈ {-0.4293, 2.3293}
1) This is a combination, so use ⁴⁰C₂.
⁴⁰C₂ = 780
There are 780 handshakes in total.
2) I got my solution by using the combinations formula. Or another way you could do this is to add up... 39 + 38 + 37 + 36 + 35 + 34 + 33 + 32 + 31... +1. You will end up with 780 (I did this to double check my work).
3) The quickest way to figure this out if Drake invited 1,000 people is to use the natural numbers formula = n(n+ 1)/2.
Plug the numbers in: 999(1000)/2 = 499,500
If Drake invited 1,000 people, there would be 499,500 handshakes.
Answer:
If this answer is correct please make me as a brainlist
Answer:
Option C
Step-by-step explanation:
(7x^3y^3)^2
= (7)^2 * (x^3)^2 * (y^3)^2
= 49 * x^(3*2) * y^(3*2)
= 49x^6y^6
You have to distribute the terms in "7x^3 * y^3" each to the power of 2
(7)^2 * (x^3)^2 * (y^3)^2
Now you can apply the rule "(x^a)^b = x^a*b" and further simplify the expression
