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slamgirl [31]
2 years ago
7

The figure shows two parallel lines cut by a transversal.

Mathematics
2 answers:
max2010maxim [7]2 years ago
5 0

Answer: D and E

Step-by-step explanation:

polet [3.4K]2 years ago
5 0

Answer:

Step-by-step explanation:

∠D and ∠E ;    ∠C and ∠F

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Sung is going to rent a truck for one day. There are two companies he can choose from, and they have the following prices.
Alexus [3.1K]

Answer:

Step-by-step explanation:

Use the equation

89 < 75 + 0.7*M                Subtract 75 from both sides

89 - 75 < 0.7M                  Combine

14 < 0.7 M                          Divide both sides by 0.7

14/0.7 < M

20 < M

If M goes over 20 then the flat rate is cheaper.

8 0
2 years ago
What do e and f equal?
Aleks04 [339]
They both equal 78 degrees because they are the same angle which means that they have the same degrees for f and e. 
6 0
3 years ago
Need help answering question​
-Dominant- [34]
I think it’s the 7.49
7 0
3 years ago
There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl
insens350 [35]

We're told that

P(A\cap B)=0.15

P(A\cup B)^C=0.06\implies P(A\cup B)=0.94

P(B\mid A)=P(B^C\mid A)=0.5

where the last fact is due to the law of total probability:

P(A)=P(A\cap B)+P(A\cap B^C)

\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)

\implies 1=P(B\mid A)+P(B^C\mid A)

so that B\mid A and B^C\mid A are complementary.

By definition of conditional probability, we have

P(B\mid A)=P(B^C\mid A)

\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}

\implies P(A\cap B)=P(A\cap B^C)

We make use of the addition rule and complementary probabilities to rewrite this as

P(A\cap B)=P(A\cap B^C)

\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)

\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)

\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]

\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]

\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C

\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)

By the law of total probability,

P(B)=P(A\cap B)+P(A^C\cap B)

\implies P(A^C\cap B)=P(B)-P(A\cap B)

and substituting this into (*) gives

2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]

\implies P(B)=P(A\cup B)-P(A\cap B)

\implies P(B)=0.94-0.15=\boxed{0.79}

8 0
3 years ago
Insert each of the following numbers between two consecutive multiples of 5: 13 37 48 61 93
DedPeter [7]
10 (13) 15
35 (37) 40
45 (48) 50
60 (61) 65
90 (93) 95
7 0
2 years ago
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