(a) 5^31-5^29 = 5^29(5^2-1)
= 5^29(24)
= 5^29(6)(4)
=5^26(6)*[(5)(5)(4)]
=5^26(6)*100
(b) 25^9+5^17 = 5^18+5^17
=5^17(5+1)
=5^17(6)
=5^16[(5)(6)]
=5^16*30
(c) 27^10–9^14 = 3^30-3^28
=3^28(3^2 -1)
=3^28(8)
=3^27[(3)(8)]
=3^27*24
If she stopped at 8;05, and she started 20 minutes earlier, just imaging a clock at 8:05 and turn back time 20 minutes.
Five minutes would be 8:00, ten minutes is 7:55, fifteen minutes is 7:50, and twenty minutes is 7:45. This, she started at 7:45
Equation of a line is given by y = mx + b; where m is the slope and b is the y-intercept.
In the given equation, y = -13x + 56k; b = -10
56k = -10
k = -10/56 = -5/28
Answer:
23
Step-by-step explanation: YAY
