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dmitriy555 [2]
3 years ago
7

Your small remodeling business has two work vehicles. One is a small passenger car used for job-site visits and for other genera

l business purposes. The other is a heavy truck used to haul equipment. The car gets 25 miles per gallon (mpg). The truck gets 10 mpg. You want to improve gas mileage to save money, and you have enough money to upgrade one vehicle. The upgrade cost will be the same for both vehicles. An upgraded car will get 40 mpg; an upgraded truck will get 12.5 mpg. The cost of gasoline is $3.30 per gallon. Calculate the annual fuel savings, in gallons, for the truck and car assuming both vehicles are driven 8,000 miles per year. (Round your answers to 2 decimal places, e.g., 32.16.)
Business
1 answer:
klemol [59]3 years ago
3 0

Answer:

Annual savings= $924

Explanation:

Giving the following information:

The car gets 25 miles per gallon (mpg). The truck gets 10 mpg. You want to improve gas mileage to save money, and you have enough money to upgrade one vehicle. The upgrade cost will be the same for both vehicles. An upgraded car will get 40 mpg; an upgraded truck will get 12.5 mpg. The cost of gasoline is $3.30 per gallon. Calculate the annual fuel savings, in gallons, for the truck and car assuming both vehicles are driven 8,000 miles per year.

Current cost= (8,000/25)*3.30 + (8,000/10)*3.30= $3,696

New cost= (8,000/40)*3.3 + (8,000/12.5)*3.3= $2,772

Annual savings= 3,696 - 2,772= $924

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A market segment is a group of individuals or organizations who share one or more characteristics.
Anastaziya [24]

Answer: True

Explanation: A part of population having one or more characteristics, grouped together for the purpose of marketing is called market segmentation. Market segmentation population have two or more common characteristics.

Market segmentation can be done on various different basis like geography, age or gender etc.

Hence, from the above explanation we can conclude that the statement is true.

6 0
3 years ago
A department that is capital-intensive most likely would use a predetermined departmental overhead rate based on which of the fo
JulijaS [17]

Answer:

D)machine hours

Explanation:

It should be noted that department that is capital-intensive most likely would use a predetermined departmental overhead rate based on

machine hours.

A machine-hour can be regarded as measurement that is been used in applying factory overhead to manufactured goods. It's application is usually found in machine-intensive environments, environment whereby the amount of time that is expelled on processing by a machine is been regarded as largest activity that overhead allocations can be said to have based upon. Machine hour rate can be gotten by making division of the total running expenses of a machine by estimated number of hours for the machine to work at a specific period

8 0
3 years ago
Sally is a high school math teacher. In 2019, she purchases $400 worth of supplies related to her teaching. Her spouse, Gabe, is
lina2011 [118]

Answer:

$350

Explanation:

The computation of AGI educator's expenses deduction is shown below:-

Since both Sally and Gabe are qualified educators, they can subtract up to $250 into business expenses and $500, but not more than $250 each if they are married.

So, Sally can deduct up to $250 from its cost and Gabe can less all of its $100 cost.

AGI educator expenses = Deduction amount from the cost + Expense in education supplies

= $250 + $100

= $350

4 0
3 years ago
Question 2 (1 point)
Soloha48 [4]
Excise, it's an extra tax which makes you pay more
6 0
3 years ago
Read 2 more answers
1. You have $10,000 to invest in a stock portfolio. Your choices are Stock X with an expected return of 11.5 percent and Stock Y
zimovet [89]

Answer:

1. Investment in X = $6900

2. Investment in Y = $3,100

Explanation:

Since the total weight of a portfolio must equal 1 (100%), the weight of Stock Y mustbe one minus the weight of Stock X. Mathematically speaking, this means:

E(RP) = .1085 = .115wX + .094(1 – wX)

.1085 = .115wX + .094 – .094wX

.0145 = .021wX

wX = 0.69

So, the dollar amount invested in Stock X is the weight of Stock X times the total portfolio value, or:

Investment in X = 0.69 ($10,000) = $6,900

And the dollar amount invested in Stock Y is:

Investment in Y = (1 – 0.69)($10,000) = $3,100

4 0
3 years ago
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