The correct answer is option D, that is, redwood tree forests.
Gymnosperms are seed-bearing vascular plants, in which the seeds or ovules are not enveloped in an ovary. In gymnosperms, the pollen is the male reproductive part, and the cone is the female reproductive part. It includes cycads, conifers, and ginkgo.
The redwood trees are examples of gymnosperms and play an essential role in sustaining the equilibrium of carbon dioxide in the atmosphere, like green plants.
The DNA microarray is a technology that is used to identify whether a specific person's DNA has mutations in genes like BRCA1 and BRCA2 which cause cancer.
- Therefore, a microarray assesses the quantity of mRNA transcripts in a sample, A genome-wide perspective of gene expression in cancer can be obtained since thousands of gene fragments can be found on an array.
- The idea behind microarrays is that sequences that are complimentary to one another will bind to one another.
- Restrictions endonucleases fragment the unidentified DNA molecules, which are then labeled with fluorescent dyes.
- These are then given a chance to interact with DNA chip probes.
- Chemotherapy has a positive effect on one group while having a negative effect on the other.
- Gene-expression microarrays have shown that the two groups' gene-expression patterns differ.
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I remember the secondary structure by visualizing it. Understand that primary structure is just the order of the amino acids. The tertiary structure is the 3dimensional configuration of the whole protein molecule with multiple interactions guiding its fold (disulfide bonds, ionic interactions, hydrogen bonds, van der walls). Secondary structure is a step towards the conformation of the protein where it is made up of either alpha-helices or beta-pleated sheets. The alpha helices look like a spiraling staircase while the beta-pleated sheets look like a repetition of long loops. These two structures hold itself by hydrogen bonds.
D. a person at rest begins to move heavy boxes of a flight of stairs
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).