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cricket20 [7]
3 years ago
6

What is the square root of 5 divided by the square root of 15 and simplify and in fraction form​

Mathematics
1 answer:
ozzi3 years ago
4 0

Answer:

\sqrt{\frac{1}{3} }

or

\frac{\sqrt{3} }{3}

Step-by-step explanation:

The expression \frac{\sqrt{5} }{\sqrt{15} } can be simplified by first writing the fraction under one single radical instead of two.

\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }

5/15 simplifies because both share the same factor 5.

It becomes \sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }

This can simplify further by breaking apart the radical.

\sqrt{\frac{1}{3} }  = \frac{\sqrt{1} }{\sqrt{3} }  = \frac{1}{\sqrt{3} }

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} }  =\frac{\sqrt{3} }{3}

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Explain how to determine the zeros of f(x)=(x+3)(x-1)(x-8)
spin [16.1K]

Answer:

x=-3,  x=1,  x=8

Step-by-step explanation:

When you have to find the zero of an equation like (x+3) all you have to do is solve for x.

x+3=0           equal the equation to zero

x+3-3=0-3    cancel out 3

x=-3              answer


If you have to find the zero of an equation like f(x)=-2x^2 - 5x + 7 then you would have to factor the equation.

7*-2=-14   multiply

-7 & 2   find the two numbers that when multiplied =14 and when added = -5

(2x^2 + 2)  (-7x + 7)  replace -5 with -7 & 2

-2x (x - 1)   -7 (x - 1)   factor

(x - 1)   (-2x - 7)    rewrite

1st: x - 1 = 0

          x = 1 : Answer

2nd: -2x - 7= 0

        -2x - 7 + 7 = 0 + 7

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        -2x / -2 = 7 / -2

          x = 7 / -2 : Answer





7 0
3 years ago
Read 2 more answers
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