Given that the first spinner has three equal sectors labelled 1, 2 and 3; and the second spinner has equal sectors labelled 3, 4, 5 and 6.
The number of possible outcomes that do not show a 1 on the first spinner is 2 (i.e. the first spinner shows 2 or 3).
The number of possible outcomes that the second spinner show the number 4 is 1 (i.e. the second spinner shows 4)
In probability, the word 'and' goes with multiplication.
Therefore, <span>the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner</span> is given by 2 x 1 = 2 possible outcomes.
i.e. the first spinner shows the number 2 and the second spinner shows the number 4 or the first spinner shows the number 3 and the second spinner shows the number 4.
I think the answer is D all of the above
Here is a link to help you find the answer:
https://www.khanacademy.org/math/algebra2/rational-expressions-equations-and-functions/simplify-rati...
Hope this helps!
2: 14+15d+9c
3: a.
ignore this I need 20 characters.:)))
Answer:
x=-3, x=1, x=8
Step-by-step explanation:
When you have to find the zero of an equation like (x+3) all you have to do is solve for x.
x+3=0 equal the equation to zero
x+3-3=0-3 cancel out 3
x=-3 answer
If you have to find the zero of an equation like f(x)=-2x^2 - 5x + 7 then you would have to factor the equation.
7*-2=-14 multiply
-7 & 2 find the two numbers that when multiplied =14 and when added = -5
(2x^2 + 2) (-7x + 7) replace -5 with -7 & 2
-2x (x - 1) -7 (x - 1) factor
(x - 1) (-2x - 7) rewrite
1st: x - 1 = 0
x = 1 : Answer
2nd: -2x - 7= 0
-2x - 7 + 7 = 0 + 7
-2x = 7
-2x / -2 = 7 / -2
x = 7 / -2 : Answer