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3 years ago

13

Complete the function table below for the function F(x) = x2 + 1.

2 answers:

gladu [14]3 years ago

8 0

The answer is actually False.

VMariaS [17]3 years ago

5 0

The answer is true, and let me explain this to you like this:
<span>F(x) = 4x - 6
when x = 1, F(x) = 4 * 1 - 6 = -2
when x = 2, F(x) = 4 * 2 - 6 = 2
when x = 3, F(x) = 4 * 3 - 6 = 6
when x = 4, F(x) = 4 * 4 - 6 = 10
</span><span>second row is: -2, 2, 6, 10
</span><span>differences are: 2 - (-2) = 4; 6 - 2 = 4; 10 - 6 = 4
</span>So, the <span>second row is in arithmetic progression.
Hope this is what you were looking for</span>

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3 years ago

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konstantin123 [22]

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3 years ago

in a certain year the average e-mail user sent or received 148 e-mails each day. The number of e-mails received was 4 more than

Lorico [155]

Answer:

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Step-by-step explanation:

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3 years ago

Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

3 years ago

Having a hard time finding the area

Marina CMI [18]

Answer:

For the triangle, the area is 7.5 in.

For the trapezoid, the area should be 90 cm

Step-by-step explanation:

The formula for a triangle is A=1/2bh and for a trapezoid it is (a+b)/2×h

5 0

3 years ago