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Snezhnost [94]
3 years ago
11

Andrew withdrew $332.55 from his savings account. He now has at most $529.71. How Much cash did he originally have?

Mathematics
1 answer:
Art [367]3 years ago
7 0
Andrew originally had $197.16
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Which function is being graphed below?
Keith_Richards [23]

The absolute function will be f(x) = | x - 5 | - 4.

<h3 /><h3>What is an absolute function?</h3>

The absolute function is also known as the mode function. The value of the absolute function is always positive.

The absolute function is given as

f(x) = | x - h | + k

Where h,k is the vertex of the absolute function.

f(x) = | x - 5 | - 4

Therefore the absolute function will be f(x) = | x - 5 | - 4.

More about the absolute function link is given below.

brainly.com/question/10664936

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4 0
2 years ago
13x+y=4 plz help i cant get it right lol
kati45 [8]

Answer:

4

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13

Step-by-step explanation:

look up top for explanation

7 0
3 years ago
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What is an ordinary annuity?
masha68 [24]

Answer:

An ordinary annuity is a series of equal payments made at the end of consecutive periods over a fixed length of time. The opposite of an ordinary annuity is an annuity due, in which payments are made at the beginning of each period.

Step-by-step explanation:

7 0
3 years ago
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A used car costs $6,472. A down payment of $1,000 is required. The remaining balance is to be paid in 36 equal monthly payments.
blondinia [14]
The answer should be $152.

$6,472 - $1,000 = $5,472
Divide $5,472 by 36 and you end up with $152.
8 0
3 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
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