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Nina [5.8K]
3 years ago
7

Do I always simplify a question before doing the operations? For example, do I always simplify a fraction before doing the opera

tions?
For example for this question:
(8-4√2) /2 + ( 6+4√2)/ 2

I had to simplify the fraction by factoring, cancelling and then do the operation or I got it wrong.
Mathematics
1 answer:
blagie [28]3 years ago
5 0

Answer:

see below

Step-by-step explanation:

it will be easier to do calculations later if you simplify first

in this case you did the best and shortest way

you could rewrite

(8-4√2) /2 + ( 6+4√2)/ 2 as

4-2\sqrt{2}  + 3 + 2\sqrt{2} and then 7 + 4\sqrt2

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Answer:

3 (Anna) + 5 (Todd) = 8

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A two-way frequency table is shown below that displays the relationship between the region of the country in which people live a
nataly862011 [7]

Answer:

13%

Step-by-step explanation:

Given the two way frequency table :

Country Music Rock Total

West 26 15 41

East 24 22 46

South 7 33 40

North 41 25 66

Total 98 95 193

From. The table :

n(West n Country music) = 26

n(Total) = 193

P(West n Country music) = n(West n Country music) / n(Total)

P(West n Country music) = 26 / 193

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What expressions are equivalent to 12x-10-6x
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Answer:

116 99.99999% sure

Step-by-step explanation:

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You have a dozen eggs at home, and you know that with them you can make 100 muffins. if you find that half of the eggs have gone
BaLLatris [955]
12 eggs: 100 muffins 
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4 years ago
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What would be the missing values for this
sergiy2304 [10]

Given:

$x^{2} y^{8} \cdot \frac{x^{3} y^{?}}{x y^{3}}=x^{4} y^{2}

To find:

The missing value.

Solution:

Let the missing value be m.

$x^{2} y^{8} \cdot \frac{x^{3} y^{m}}{x y^{3}}=x^{4} y^{2}

Using exponent rule: a^m \cdot a^n=a^{m+n}

$ \frac{x^{2+3} y^{8+m}}{x y^{3}}=x^{4} y^{2}

$ \frac{x^{5} y^{8+m}}{x y^{3}}=x^{4} y^{2}

Using exponent rule: \frac{a^m}{a^n} =a^{m-n}

$ x^{5-1} y^{8+m-3}=x^{4} y^{2}

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x^4=x^4 and y^{5+m}=y^2

If the bases are same, then the powers are equal.

5+m=2

Subtract 5 from both sides.

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