Answer:
Step-by-step explanation:
1) Surface area of a square = s*s = 12*12 = 144 in
2) Surface area of a Cone = A=πr(r+h2+r2) = 3.142*4(4+22*2+4*2) = 351.904 cm^2
3) S.A of a Cylinder =2πrh+2πr2 = 2*3.142*2*14 + 2*3.142*2*2 = 201.088 m^2
4) S.A of a square Pyramid = a^2 + 2a squareroot (a^2/4 + h^2) = 516.5m^2
5) S.A of a Sphere = 4*pie*r^2 = 4* 3.142*15^2 = 2827.8mm^2
Add 2p² to each side of the equation. Then you have
2p² + 16p + 24 = 0 .
Before you roll up your sleeves and start working on it, you can make it
even more convenient if you divide each side by 2 . Then you have:
p² + 8p + 12 = 0 .
Now you have a nice, comfortable, familiar-looking quadratic equation.
You can either factor the left side into (p + 6) (p + 2), or, if you can't find
the factors, you can apply the quadratic formula to it.
That's how to solve it, and find its two solutions.
Solution:
Given that the point P lies 1/3 along the segment RS as shown below:
To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have
Using the section formula expressed as
![[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D%2C%5Cfrac%7Bmy_2%2Bny_1%7D%7Bm%2Bn%7D%5D)
In this case,
where
Thus, by substitution, we have
![\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5B%5Cfrac%7B1%282%29%2B2%28-7%29%7D%7B1%2B2%7D%2C%5Cfrac%7B1%284%29%2B2%28-2%29%7D%7B1%2B2%7D%5D%20%5C%5C%20%5CRightarrow%5B%5Cfrac%7B2-14%7D%7B3%7D%2C%5Cfrac%7B4-4%7D%7B3%7D%5D%20%5C%5C%20%3D%5B-4%2C%5Ctext%7B%200%5Crbrack%7D%20%5Cend%7Bgathered%7D)
Hence, the y-coordinate of the point P is
Answer:
$162
Step-by-step explanation:
5r=20 10p=100 14t=42
100+42+20=162
5r+10p+14t=$162
Answer:
-4 and -3
A negative times a negative results to a positive number, but when two negative numbers are added to each other, it still results to a negative number.
Hope I helped!
