<h2>
Answer:</h2><h2>n=-5</h2>
n
-
4
=
3
+
6
n-4=3n+6
n−4=3n+6
Solve
1
Add
4
4
4
to both sides of the equation
−
4
=
3
+
6
n-4=3n+6
n−4=3n+6
−
4
+
4
=
3
+
6
+
4
n-4+{\color{#c92786}{4}}=3n+6+{\color{#c92786}{4}}
n−4+4=3n+6+4
2
Simplify
3
Subtract
3
3n
3n
from both sides of the equation
4
Simplify
5
Divide both sides of the equation by the same term
6
Simplify
Answer: 10, 11, & 12
<u>Step-by-step explanation:</u>
Let x represent the age of the youngest child.
Their ages are consecutive so,
Youngest: x
Middle: x + 1
Oldest: x + 2
The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.
x² = 8(x + 2) + 4
x² = 8x + 16 + 4
x² = 8x + 20
x² - 8x - 20 = 0
(x - 10)(x + 2) = 0
x - 10 = 0 or x + 2 = 0
x = 10 or x = -2
Since age cannot be negative, x = -2 is not valid
So, the Youngest (x) is 10
the Middle (x + 1) is 11
and the Oldest (x + 2) is 12
Answer: 5 units
Step-by-step explanation:
Answer: 34 stuffed animals & 17 mystery boxes.
First off, split 51 into three parts, trying to find how much 1/3 is of 51. It equals 17.
The stuffed animals in the machine are “twice as much” of the mystery boxes, so you need to multiply 17 x 2 to find the amount of stuffed animals.
17 x 2 = 34
As for the mystery boxes, you need to multiply it by one.
17 x 1 = 17.
In summary, the answer is 34 stuffed animals and 17 mystery boxes.
Answer:
- Powers of the variable descending left to right
- right side of the equal sign is 0
Step-by-step explanation:
For some constants a, b, and c, the standard form* is ...
ax^2 + bx + c = 0
___
It is nice if the leading coefficient (a) is positive, but that is not required.
The main ideas are that ...
- Powers of the variable are descending
- All of the non-zero terms are on the left side of the equal sign
- Like terms are combined
_____
* This is the <em>standard form</em> for a quadratic. For other kinds of equations, when the expression is equal to zero, this would be called "general form."
