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mario62 [17]
3 years ago
10

What are the Database used in RDBMS and DBMSplease answer immediately​

Computers and Technology
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

The best example for the DBMS is certainly the Microsoft Access. And various examples of RDBMS are MySQL, Sql Server, Amazon DynamoDB and so on. However, its essential to understand the difference between the RDBMS and the DBMS. The main difference between the two is certainly that in the RDBMS the application stores the data in tabular manner, and DBMS the data is stored as files. In the RDBMS the tables comes with identifier known as primary key, and the data values are being saved in the form of tables.

Explanation:

Please check the answer section.

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Answer:

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Explanation:

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devlian [24]

Answer:

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Explanation:

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Write a program to implement problem statement below; provide the menu for input N and number of experiment M to calculate avera
zalisa [80]

Answer:

Explanation:

#include<iostream>

#include<ctime>

#include<bits/stdc++.h>

using namespace std;

double calculate(double arr[], int l)

{

double avg=0.0;

int x;

for(x=0;x<l;x++)

{

avg+=arr[x];

}

avg/=l;

return avg;

}

int biggest(int arr[], int n)

{

int x,idx,big=-1;

for(x=0;x<n;x++)

{

if(arr[x]>big)

{

big=arr[x];

idx=x;

}

}

return idx;

}

int main()

{

vector<pair<int,double> >result;

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

int choice;

cin>>choice;

while(choice!=2)

{

int n,m;

cout<<"Enter N"<<endl;

cin>>n;

cout<<"Enter M"<<endl;

cin>>m;

int c=m;

double running_time[c];

while(c>0)

{

int arr[n];

int x;

for(x=0;x<n;x++)

{

arr[x] = rand();

}

clock_t start = clock();

int pos = biggest(arr,n);

clock_t t_end = clock();

c--;

running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;

}

double avg_running_time = calculate(running_time,m);

result.push_back(make_pair(n,avg_running_time));

cout<<"Enter 1 for iteration\nEnter 2 for exit\n";

cin>>choice;

}

for(int x=0;x<result.size();x++)

{

cout<<result[x].first<<" "<<result[x].second<<endl;

}

}

8 0
3 years ago
(Financial application: compound value) Suppose you save $100 each month into savings account with an annual interest rate of 5%
Nostrana [21]

Solution:

initial = float(eval(input('Enter the monthly saving amount: ')))

x = (1 + 0.00417)

month_one = initial * x

month_two = (initial + month_one) * x  

month_three = (initial + month_two) * x  

month_four = (initial + month_three) * x

month_five = (initial + month_four) * x  

month_six = (initial + month_five) * x  

print('The sixth month value is: '+str(month_six))  

Don't forget the saving amount, and initialize the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.

balance = 801

for month in range(6):

  balance = balance * (1.00417)

print(balance)

7 0
3 years ago
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Aloiza [94]

Answer:

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7 0
3 years ago
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