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Dimas [21]
3 years ago
15

_____ is the management function that monitors the performance of the firm and makes improvements when necessary

Computers and Technology
1 answer:
Katen [24]3 years ago
7 0
CONTROLLING is the management function that monitors the performance of the firm and makes improvements when necessary. When the management has control, then it would be easy to organize everything and put everything in place so that the firm will run smoothly.
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Which of these is system software? Check all
Darya [45]

Answer:

Windows OS is software....

6 0
3 years ago
Look at the logic program below. Set a breakpoint after each commented instruction. You can also single step through the program
Goshia [24]

Using programming knowledge, it is possible to use programming logic, we can differentiate and find the terms

<h3>Writing the code and understanding the programming logic:</h3>

<em>.data</em>

<em>sourceword:</em>

<em>.word 0xAB</em>

<em>wordmask:</em>

<em>.word 0xCF</em>

<em>operand:</em>

<em>.long 0xAA</em>

<em>.text</em>

<em>.globl _start</em>

<em>_start:</em>

<em>movw sourceword, %ax # ax=0x00AB ( move the word value of sourceword =0x00AB to ax register.)</em>

<em>movw %ax, %bx # bx=0x00AB ( copy the value of ax to bx register.)</em>

<em>xorw %cx, %cx # cx=0000 ( cx=cx XOR cx, that is clear cx register.)</em>

<em />

<em>andw wordmask, %ax # ax=0x008B ( ax=ax AND wordmask= 0x00AB AND 0x00CF= 0x008B)</em>

<em>orw wordmask, %bx # bx=0x00EF (bx=bx OR wordmask= 0x00AB OR 0x00CF= 0x00EF.)</em>

<em>xorw wordmask, %cx # cx=0x00CF (cx=cx XOR wordmask= 0x0000 XOR 0x00CF=0x00CF.)</em>

<em />

<em>movl operand, %eax # eax=0x000000AA. ( copy the 32-bit value of operand=0x000000AA to eax.)</em>

<em>movl %eax, %ebx # ebx=0x000000AA.( copy the value of eax to ebx.)</em>

<em>movl %eax, %ecx # ecx=0x000000AA. ( copy the value of eax to ecx.)</em>

<em />

<em>shll $3,%eax # eax=0x00000550. ( logical shift left of eax=0x000000AA by 3 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em># =>00000000000000000000010101010000=0x00000550.</em>

<em />

<em>rorl $4,%ebx # ebx=0xA000000A. (Rotate right ebx=0x000000AA by 4 bits.)</em>

<em />

<em># 0x000000AA=00000000000000000000000010101010</em>

<em />

<em>3 =>10100000000000000000000000001010= 0xA000000A.</em>

<em />

<em>sarl %ecx # here the count value to shift the bits not mentioned.</em>

<em />

<em># It is the arithmetic shift right instruction. the shifted left bits filled with MSB bit.</em>

See more about logic program at brainly.com/question/14970713

#SPJ1

5 0
2 years ago
What will be the output of the following lines of code and the user's response?
Arte-miy333 [17]

Answer:

The answer is C. 85

Explanation:

The int() function is usually used to turn a float, to an int<em>.</em> When you use the int() function, it just cuts of everything past the decimal. It doesn't round the float. Leaving you with the option C. 85

hope this helped you :D

6 0
3 years ago
What type of USB connector is always plugged into the computer to connect in external device
barxatty [35]
HDMI? I am not entirely sure
4 0
3 years ago
A bowl contains 20 candies; 15 are chocolate and 5 are vanilla. You select 5 at random. What is the probability that all 5 are c
Sindrei [870]

Answer: 0.1937

Explanation:

Given : A bowl contains 20 candies; 15 are chocolate and 5 are vanilla.

If we select 5 candies, then the number of ways to select them is given by permutations.

The number of ways to select 5 candies is given by :-

^{15}P_5=\dfrac{15!}{(15-5)!}=\dfrac{15\times14\times13\times12\times11\times10!}{10!}=360360

The number of ways of selecting any 5 candies out of 20:-

^{20}P_5=\dfrac{20!}{(20-5)!}\\\\=\dfrac{20\times19\times18\times17\times16\times15!}{15!}\\\\=1860480

Now, the probability that all 5 are chocolate :-

=\dfrac{360360}{1860480}=0.193691950464\approx0.1937

Hence, the probability that all 5 are chocolate =0.1937

5 0
3 years ago
Read 2 more answers
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