How do you write twelve and five hundred ninety-nine thousandths in standard form

Michael paid a repairman dollars per hour for a 4-hour job plus $69 for parts. The total charge was $320. Which equation can be

Stels [109]

Answer:

The answer is d) 4d = 320 - 60 becasue d is the dollors he made per hour and the repairman worked for 4 hours so you multiply 4 times d and then you subtract 60 from the total to get your final answer. If you subtracted already then you would divide that answer by 4 then you would find out how much the repairman maid per hour.

5 0

3 years ago

Please answer 2.) a and b!

KatRina [158]

1.a. correct

1.b. $\sqrt{121} - \sqrt{9} = 11 - 3 = 8$

1.c. correct

1.d. $-\sqrt{36} - \sqrt{100} = -6 - 10 = -16$

2.a. 7 - x + 3w - 9

Terms: 7, -x, 3w, -9

Variables: x, w

Coefficients: -1, 3

Constants: 7, -9

2.b. -g + 8k - 3 - 7

Terms: -g, 8k, -3, -7

Variables: g, k

Coefficients: -1, 8

Constants: -3, -7

3.a. correct

3.b. correct

3.c. -5+ 4x = -x

4.a. 4(2x + 3) = 8x + 12

4.b. -2(3x + 4) = -6x - 8

4.c. -5(2x - 3) = -10x + 15

7 0

3 years ago

If f(x)= 5x -7, what is f(3)?

Gemiola [76]

Answer:

8

Step-by-step explanation:

f(x) = 5(3) - 7

f(x) = 15 - 7

f(x) = 8

4 0

3 years ago

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Factor this expression completely.<br> 36y2 - 1

shtirl [24]

Answer:

(6y - 1)(6y + 1)

Step-by-step explanation:

To factorize completely, we may adopt the difference of 2 squares approach. The theory states that difference of two square is the product of the difference of the number and the sum of the numbers.

Such that

a² - b² = (a - b) (a + b)

Hence 36y² - 1

= 6²y² - 1²

= (6y)² - 1²

= (6y - 1)(6y + 1)

5 0

4 years ago

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Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an

lyudmila [28]

<h2>Answer:</h2>

$Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees$

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°

<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°

So the components can be found as follows:

$F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf$

So the components of the resultant force can be found by adding each component of the individual forces as follows:

$R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf$

Finally, the magnitude and direction of the resultant force is:

$Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees$

6 0

3 years ago

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