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Firlakuza [10]
3 years ago
13

Plz help !

Mathematics
2 answers:
Inessa [10]3 years ago
5 0
It’s 12 DIVIDE (7-4)+5 TIMES 3=19
KengaRu [80]3 years ago
3 0
12 divide (7-4) plus 5 x 3= 19

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A manufacturer of processing chips knows that 2\%2%2, percent of its chips are defective in some way. Suppose an inspector rando
kipiarov [429]

The data in the question seems a bit erroneous. I am writing the correct question below:

A manufacturer of processing chips knows that 2%, percent of its chips are defective in some way. Suppose an inspector randomly selects 4 chips for an inspection. Assuming the chips are independent, what is the probability that at least one of the selected chips is defective? Lets break this problem up into smaller pieces to understand the strategy behind solving it.

Answer:

The probability that at least one of the selected chips is defective is 0.0776.

Step-by-step explanation:

The question states that the probability of defective chips is 2% i.e. 0.02. Let p denote the probability of selecting a defective chip so, p = 0.02

An inspector selects 4 chips, which means n=4 and we need to compute the probability that at least one of the selected chips is defective. Let X be the number of defective chips selected. We need to compute P(X≥1) which means either 1, 2, 3 or 4 chips can be defective.

We will use the binomial distribution formula to solve this problem. The formula is:

<u>P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ</u>

where n = total no. of trials

          p = probability of success

          x = no. of successful trials

          q = probability of failure = 1-p

we have n=4, p=0.02 and q=1-0.02=0.98.

We need to compute P(X≥1) which is equal to:

P(X≥1) = P(X=1) + P(X=2) + P(X=3) + P(X=4)

A shorter method to do this is to use the total probability theorem:

P(X≥1) = 1 - P(X<1)

          = 1 - P(X=0)

          = 1 - ⁴C₀ (0.02)⁰(0.98)⁴⁻⁰

          = 1 - (0.98)⁴

          = 1 - 0.9224

P(X≥1) = 0.0776

4 0
3 years ago
There are 32 students in the orchestra and twice that number in the band. There are 19 boys and 11 girls in the choir. If each s
Mnenie [13.5K]

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. The total number of students that are in the orchestra, the band, and the choir is 126.

<h3>What is Addition?</h3>

The addition is one of the four fundamental mathematical operations, the others being subtraction, multiplication, and division. When two whole numbers are added together, the total quantity or sum of those values is obtained.

There are 32 students in the orchestra and twice that number in the band. Therefore the number of students in the band is:

Number of students in band = 2 (Number of students in Orchestra)

                                                = 2 × 32 = 64

The number of students in the Choir is the sum of the number of boys and girls. Therefore, the number of students in the Choir is,

Number of students in the Choir = 19 + 11 = 30

Total number of students = 32 + 64 + 30 = 126

hence, the total number of students that are in the orchestra, the band, and the choir is 126.

Learn more about Addition:

brainly.com/question/14092461

#SPJ1

7 0
2 years ago
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