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3 years ago

MNOP is a square. What are the values of t and f?

Mathematics

2 answers:

NeTakaya3 years ago

7 0

Answer:

t = 17.5 and f = 12

djyliett [7]3 years ago

3 0

The answer is: <span>t=17.5 and f=12
</span>
Hope this helps!!

~Lena~

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Maylin is mailing a package that has the

yarga [219]

Answer:

V=378 inch³

Step-by-step explanation:

The package is in the shape of a cuboid. The volume of a cuboid is given by :

V = lbh

l=length, b=breadth and h=height

Area of base = 54 inch²

Height of box, h = 7 in

It means that, volume of the package is :

V = 54 × 7

V=378 inch³

So, the volume of the package is 378 inch³.

3 0

3 years ago

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8)

frutty [35]

Answer:

cosФ = $\frac{1}{\sqrt{65}}$ , sinФ = $-\frac{8}{\sqrt{65}}$ , tanФ = -8, secФ = $\sqrt{65}$ , cscФ = $-\frac{\sqrt{65}}{8}$ , cotФ = $-\frac{1}{8}$

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = $\frac{x}{r}$
sinФ = $\frac{y}{r}$
tanФ = $\frac{y}{x}$
secФ = $\frac{r}{x}$
cscФ = $\frac{r}{y}$
cotФ = $\frac{x}{y}$

Where r = $\sqrt{x^{2}+y^{2} }$ (the length of the terminal side from the origin to point (x, y)

You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = $\sqrt{x^{2}+y^{2} }$

∵ x = 1 and y = -8

∴ r = $\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}$

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = $\frac{x}{r}$

∴ cosФ = $\frac{1}{\sqrt{65}}$

∵ sinФ = $\frac{y}{r}$

∴ sinФ = $-\frac{8}{\sqrt{65}}$

∵ tanФ = $\frac{y}{x}$

∴ tanФ = $-\frac{8}{1}$ = -8

∵ secФ = $\frac{r}{x}$

∴ secФ = $\frac{\sqrt{65}}{1}$ = $\sqrt{65}$

∵ cscФ = $\frac{r}{y}$

∴ cscФ = $-\frac{\sqrt{65}}{8}$

∵ cotФ = $\frac{x}{y}$

∴ cotФ = $-\frac{1}{8}$

8 0

3 years ago

What is the answer for this 9x+8=107

oee [108]

Answer:

x=11

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Logan made a treasure map he treasure is 25 cm away from his location if each 1 cm on the scale drawing equals 5 m then how far

Doss [256]

Logan is 125 meters away from the treasure.

Also, this question seems like an elementary school question, not a high school question, so why does it say that you are in high school?

8 0

3 years ago

What are the approximate solutions of 2x^2 + x = 14, rounded to the nearest hundredth?

Slav-nsk [51]

Hello,

2x²+x-14=0
Δ=1+4*14*2=113

x=(-1-√113)/4=-2,8839...≈-2.88
or x=(-1+√113)/4=2,40753≈2.41

7 0

3 years ago