Answer:
The repulsive electrostatic force between two of the protons is 14.4 N.
Explanation:
Given;
distance between the two protons, r = 4 x 10⁻¹⁵ m
charge of a proton, q = + 1.6 x 10⁻¹⁹ C
The repulsive electrostatic force between two of the protons is calculated by applying Coulomb's law;
Therefore, the repulsive electrostatic force between two of the protons is 14.4 N.
Answer:
The magnitude of the magnetic field is .
Explanation:
Given that,
Charge,
Speed of the charged particle,
The angle between the velocity of the charge and the field is 56°.
The magnitude of force,
We need to find the magnitude of the magnetic field. When a charged particle moves in the magnetic field, the magnetic force is experienced by it. The force is given by :
B is the magnetic field.
So, the magnitude of the magnetic field is . Hence, this is the required solution.
Generator bc. It makes light
Answer:
Its new current will be 240.0milliAmps
Explanation:
According to ohms law,
V = IR
V is the supply voltage in a circuit
I is the current
R is the resistance
If the current in the wires of a circuit is 120.0 milliAmps, the voltage will be:
V1 = 120R1
R1 = V1/120...(1)
If the voltage impressed across the ends of the circuit were doubled (with no change in its resistance),
V2 = 2V1
V2 = IR2
2V1 = IR2
R2 = 2V1/I ... (2)
Since there are no changes in resistance
R1 = R2
Equating 1 and 2, we have:
V1/120 = 2V1/I
1/120 = 2/I
Cross multiplying
I = 2×120
I = 240milliAmps