Answer:
23.7402 m
21.582 m/s
310.521816 m/s²
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
g = Acceleration due to gravity = 9.81 m/s² = a
Equation of motion

The drop distance is 23.7402 m

When they hit the air bags at the bottom of the tower the speed of the experiments is 21.582 m/s
The final speed of the fall will be the initial velocity of stopping

The average stopping acceleration is 310.521816 m/s²
Answer:
The area of the portion of the wall that will be painted is 105 square feet
Explanation:
Total area of wall = 12 × 10 = 120 ft²
The area of the wall that will not be painted = area of the blackboard = 5 × 3 = 15 ft²
So, the area of the wall to be painted = Total area of wall - Area of the wall that will not be painted = 120 - 15 = 105 ft²
Answer:
A = 1.4 m/s²
B = -0.10493 m/s³
a = 1.29507 m/s²
T = 28095.8271 N
T = 1.13198 W
Explanation:
t = Time taken
g = Acceleration due to gravity = 9.81 m/s²
The equation

Differentiating with respect to time

At t = 0

Hence, A = 1.4 m/s²

B = -0.10493 m/s³
At t = 5 seconds

a = 1.29507 m/s²

T = 28095.8271 N
Weight of rocket


T = 1.13198 W
Newton's 2nd law of motion:
Force = (mass) x (acceleration)
Divide each side
by 'acceleration': Mass = (force) / (acceleration)
= (2,500 N) / (200 m/s²)
= 12.5 kg