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steposvetlana [31]
4 years ago
8

Compare and contrast the general characteristics of a gas giant planet and one of the inner planets (such as Mercury, Earth, Ven

us or Mars)? Give two differences and one similarity.
Physics
1 answer:
yKpoI14uk [10]4 years ago
6 0
The gas planets usually have extremely high gravitational pulls, the surface isn't solid (since its a gas planet), and gas planets are larger than the inner planets. 
<span>Similarities- These planets all have moons and they both revolve around the sun (obviously).


Hope this helps.</span>
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Which chemical in tobacco smoke may damage cilia in the respiratory
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8 0
3 years ago
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A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 N. What must be done to f
Llana [10]
-The force of gravity must be broken into its parallel and perpendicular components.-Acceleration can be found by dividing the net force by mass.-Trigonometry can be used to solve for the magnitude of the force components.<span>-Net force must be found before acceleration can be found.</span>
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4 years ago
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You are traveling in a convertible with the top down. The car is moving at a constant velocity 28.9 m/s, due east along flat gro
faltersainse [42]

Answer:

91.914138 m

Explanation:

t = Time taken

u = Initial velocity = 15.6 m/s

v = Final velocity = -15.6 m/s (it will hit the ground at this speed)

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{-15.6-15.6}{-9.81}\\\Rightarrow t=3.18042\ s

Distance=Speed\times Time

d=3.18042\times 28.9\\\Rightarrow d=91.914138\ m

The distance the car will travel is 91.914138 m

6 0
3 years ago
David is driving a steady 26.0 m/s when he passes tina, who is sitting in her car at rest. tina begins to accelerate at a steady
nata0808 [166]

Relative speed of Tina with respect to David is given by

v_r = v_t - v_d

v_r = 0 - 26

v_r = - 26 m/s

now the acceleration of Tina with respect to David

a_r = a_t - a_d

a_r = 2.80 - 0

a_r = 2.80 m/s^2

now the relative displacement would be zero when Tina cross David

so now we have

\deta x = 0 = v_r * t + \frac{1}{2} a_r t^2

0 = -26 * t + \frac{1}{2}*2.8*t^2

t = 18.6 s

now the speed of Tina at this moment is given as

v_f = v_i + a * t

v_f = 0 + 2.8 * 18.6

v_f = 52 m/s

<em>so the speed will be 52 m/s</em>

5 0
3 years ago
A cyclotron is designed to accelerate protons (mass 1.67 x 10^-27 kg) up to a kinetic energy of 2.5 x 10^-13 J. If the magnetic
Dafna11 [192]

Answer:

24 cm

Explanation:

Given:

Mass of proton = 1.67 × 10⁻²⁷ Kg

kinetic energy = 2.5 × 10⁻¹³ J

magnetic field in the cyclotron, B = 0.75 T

Now,

Kinetic energy = \frac{1}{2}mv^2  = 2.5 × 10⁻¹³ J

where, v is the velocity of the electron

or

\frac{1}{2}\times1.67\times10^{-27}\times v^2  = 2.5 × 10⁻¹³ J

or

v² = 2.99 × 10¹⁴

or

v = 1.73 × 10⁷ m/s

also,

centripetal force = magnetic force

or

\frac{mv^2}{r}  = qvB

q is the charge of the electron

r is the radius of the dipole magnets

on substituting the respective values, we get

\frac{1.67\times10^{-27}\times1.73\times10^7}{r}  = 1.6 × 10⁻¹⁹ × 0.75

or

r = 0.2408 m ≈ 24 cm

Hence, the correct answer is 24 cm

6 0
3 years ago
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