The formula for the volume of a pyramid is,
V=1/3Bh
Since the base of the pyramid is a square, the base area is 11^2
which equals 121 sq. units
So, substitute 121
for B
and 6 for h, in the formula.
V=1/3(121)(6) = 242 cu. units
Or alternatively 1/3(11^2)(6) = 242 cu. units
Answer:
Step-by-step explanation:
<u>Use both points and find the slope:</u>
- m = (1 - 4) / (8 - 4) = - 3/4
<u>Find the line, using point-slope form and point (4, 4):</u>
- y - 4 = - 3/4(x - 4)
- y - 4 = - 3/4x + 3
- y = - 3/4x + 7
Answer:
12
Step-by-step explanation:
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
6r^2 + 7r + 8 = 6
6r^2 + 7r + 2 = 0
Now this one is difficult to factor so i will use quadratic equation:
[-b (+-) sqrt (b^2 - 4ac)] / (2a)
we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c
so
[-7 (+-) sqrt (7^2 -(4)(6)(2)] / (2) (6)
[-7 (+-) sqrt (49 - 48)] / 12
[-7 (+-) 1] /12
split into the + and - for 2 answers
(-7 + 1) / 12
-6/12
-1/2
And
(-7 -1) /12
-8 / 12
-2/3
those are.the 2 answers
But but it says largest so -1/2
