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marusya05 [52]
3 years ago
6

Find the standard form of the equation of the parabola with a focus at (-2, 0) and a directrix at x = 2.

Mathematics
1 answer:
7nadin3 [17]3 years ago
3 0

Answer:

y^2=-8x

Step-by-step explanation:

The directrix intersects the x-axis at point (2,0). Points (-2,0) and (2,0) are symmetric about the origin, so the vertex of the parabola is placed at the origin (0,0).

The parameter p of the parabola is the distance from the focus to the directrix, thus p=4.

The branches of the parabola go in negative direction of x-axis, because the focus lies to the left from the vertex.

The equation of the parabola is

(y-0)^2=-2\cdot 4\cdot (x-0),\\ \\y^2=-8x.

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Answer:

the third one ig

Step-by-step explanation:

6 0
3 years ago
The sum of two polynomials is 10a2b2 – 8a2b + 6ab2 – 4ab + 2. If one addend is –5a2b2 + 12a2b – 5, what is the other addend?
julsineya [31]

Answer:

25a2b2+4a2b+6ab2-4ab+7

Step-by-step explanation:

=sum of two polynomials -one addend

=20a2b2-8a2b+6ab2-4ab+2-(-5a2b2+12a2b-5)

=20a2b2-8a2b+6ab2-4ab+2+5a2b2-12a2b+5

=25a2b2+4a2b+6ab2-4ab+7

8 0
2 years ago
If John is 6 and his brother is 2 times his age how old is his brother
tangare [24]

Answer:

Hey!

Your answer is that John's brother is 12 years old!

Step-by-step explanation:

If in the question it says "2 times" you just multiply the subject by 2

In this case it is 6 x 2 = 12

So his brother is 12 years of age!

HOPE THIS HELPS!!

8 0
3 years ago
Help my homework pls!!!!!!​
Hitman42 [59]

Answer:

(2x^2 + x-3)/(4x^2-9)

Step-by-step explanation:

The denominator looks like an expression in which we have applied the difference of two squares to

In that case, we know that;

a^2-b^2 = (a-b)(a+ b)

That means we would be have 2x + 3 as the other denominator factor and the expression at the denominator would be;

(2x + 3)(2x-3) = 4x^2 - 9

Also, we would have to cancel out 2x + 3 from the numerator too, so as to be left with only the binomial

That means;

(2x+3)(x-1) = 2x^2-2x+ 3x - 3 = 2x^2+x -3

So we have the original expression as;

(2x^2 + x-3)/(4x^2-9)

4 0
3 years ago
We say that an integer a is a type 0 integer if there exists an integer n such that a = 3n. An integer a is a type 1 integer if
Delicious77 [7]

Answer:

<em>Proof below</em>

Step-by-step explanation:

Let's assume a is a type 1 integer. By definition, it means we can find an integer n such that

a=3n+1

We need to prove a^2 is a type 1 integer

Expanding

a^2=(3n+1)^2=9n^2+6n+1

If a^2 is a type 1 integer, then we should be able to find an integer m such as

a^2=3m+1

Equating

a^2=3m+1=9n^2+6n+1

solving for m

m=3n^2+2n

Since we know n is an integer, then the expression of m gives an integer also. Having found the required integer m, the assumption is proven

5 0
3 years ago
Read 2 more answers
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