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denis23 [38]
3 years ago
8

Q #5 please I need your help

Mathematics
1 answer:
mojhsa [17]3 years ago
4 0

"Standard form" is the form ...

... ax +by = c

where a, b, c are mutually prime integers and the leading coefficient is positive. (If a ≠ 0, then it is "leading". If a = 0, then b is the leading coefficient.)

Of the choices offered, the only one that is equivalent to the given equation is ...

... -x + 6y = 5

_____

However, "standard form" requires the leading coefficient be positive, so an appropriate answer would be ...

... x -6y = -5

or

... 6y -x = 5

____

This is another one for my "broken question" file.

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Find the product of the following:<br>(i) 5 (-4)<br>(ii) (-8) (-6)​
harkovskaia [24]

Answer: i believe it is 960

Step-by-step explanation:

8 0
3 years ago
Find a number whose product with 7 is the same as its sum with 18
SSSSS [86.1K]
7 + 18 = 25
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7 0
3 years ago
If (angle)1 = 7x and (angle)4 = 3x + 20, what is the value of x?
Semenov [28]
The value of x is 5. Angle one and four are vertical. You can do this by writing 7x = 3x + 20. Isolate the variable by moving 3x to the other side. If you do this, 3x becomes negative, and you end up with 7x-3x = 20 --> 4x = 20.
x=5.
7 0
3 years ago
Read 2 more answers
What is the midpoint of the line segment with endpoints(-2,-2) and (4,6)
Ann [662]

Answer:

The midpoint of points (-2,-2)\ and\ (4,6) is (1,2).

Step-by-step explanation:

Given points are (-2,-2)\ and\ (4,6). We need to find the midpoint of the line segment.

The formula of finding midpoints between the point (x_1,y_1)\ and\ (x_2,y_2) is

(\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2})\ Equation(1)

W have points (x_1,y_1)=(-2,-2). And (x_2,y_2)=(4,6)

Let us plug the value in Equation (1)

(\frac{-2+4}{2} ),(\frac{-2+6}{2})

(\frac{2}{2}),(\frac{4}{2})\\ \\(1,2)

So, the midpoint of points (-2,-2)\ and\ (4,6) is (1,2).

3 0
3 years ago
Which of the following is not a correct description of the graph of the function y = -2x - 7?
swat32
The graph of the function contains the points (0,-7), (1,-9), and (3,-1) is incorrect

it contains all the points except the last set...(3,-1)
y = -2x - 7
-1 = -2(3) - 7
-1 = -6-7
-1 = - 13 (incorrect)
7 0
3 years ago
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